Help me graph it please

Mathematics

1 answer:

VikaD [51]3 years ago

8 0

Here's a rough graph haha
the graph has a factor of 4/1 (considered the "slope"), and the vertex is translated 2 units to the right (whatever is in the | lines | has the negative/positive flipped), and 6 units down.

You might be interested in

Here is the histogram of a data distribution. All class widths are 1.

JulsSmile [24]

Median is 6 so your answer is C

8 0

3 years ago

If the mountain at a convergent plate boundary is growing at a rate of 1.6 mm per year, how much higher will it be in 50 years ?

Mrrafil [7]

The mountain will be at 80mm long in 50 years because 50 times 1.6mm equals 80

5 0

2 years ago

Graph 14x+34y=1 pretty please with a cherry on top!Also thank-you

Svetlanka [38]

To make it much easier, it should be converted to the slope-intercept form
y = mx + b

To do so, 14x + 34y = 1 turns to:
34y = -14x + 1

Divide both sides by 34:
$\frac{34y}{34} = \frac{-14}{34} x + \frac{1}{34}$
Simplified:
$y = \frac{-7}{17} x + \frac{1}{34}$

Answer: $y = -\frac{7}{17} x + \frac{1}{34}$
Here is the graph:

4 0

3 years ago

Quadrilateral DEFG has vertices D(−2,4) , E(4,7) , F(10,3) , and G(8,0) .

fredd [130]

A rotation 270° counterclockwise about the origin is the same as rotation 90° clockwise about the origin and has a rule:

(x,y)→(y,-x).

Then:

D(−2,4)→D'(4,2)
E(4,7)→E'(7,-4)
F(10,3)→F'(3,-10)
G(8,0)→G'(0,-8)

Answer: the coordinates of vertices of quadrilateral D′E′F′G′ are D'(4,2), E'(7,-4), F'(3,-10), G'(0,-8).

8 0

2 years ago

A flagpole casts a shadow 16 feet long.

Triss [41]

Step-by-step explanation:

Since Shanika is standing near the pole, we can safely assume that the triangle formed by Shanika and her shadow is a smaller version of the triangle formed by the pole and its shadow.

By similar triangles:

$\frac{x \: of \: pole}{y \: of \: pole} = \frac{x \: of \: shanika}{y \: of \: shanika} \\ \frac{16}{ height \: of \: pole} = \frac{4}{5} \\ 16(5) = 4 \times height \: of \: pole \\ height \: of \: pole = \frac{80}{4} \\ = 20$

The height of the pole is 20ft.

7 0

3 years ago