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irga5000 [103]
3 years ago
6

What is the square root of 144 + 14

Mathematics
2 answers:
olasank [31]3 years ago
7 0
It would be 12.57...
Mariulka [41]3 years ago
5 0
So first to get this you add 144 and 14 together and get 158. Then we can just put this in calculator and get 12.56980509, but usually you would round it to the nearest hundredth and that would be 12.57.
Hope this helps!
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Hillary earns $60 per week at her job, plus $2 for each item she sells. She wants to
AnnZ [28]

Answer:

60+2x≥300

Step-by-step explanation:

So we know that she makes a base of $60 a week and gets $2 extra for every item she sells. First, we set up an equation for how many items she would have to sell to make exactly $300 in a week. 60+2x=300. Now, all we do is replace the equal sign with a ≥ sign because it says at least which means more than or equal to.

8 0
2 years ago
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Pi + pi/2 bằng bao nhiêu
ki77a [65]
3/2pi nha má, bấm máy đi
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3 years ago
Use spherical coordinates to find the volume of the region that lies outside the cone z = p x 2 + y 2 but inside the sphere x 2
Harman [31]

I assume the cone has equation z=\sqrt{x^2+y^2} (i.e. the upper half of the infinite cone given by z^2=x^2+y^2). Take

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

The volume of the described region (call it R) is

\displaystyle\iiint_R\mathrm dx\,\mathrm dy\,\mathrm dz=\int_0^{2\pi}\int_0^{\sqrt2}\int_{\pi/4}^\pi\rho^2\sin\varphi\,\mathrm d\varphi\,\mathrm d\rho\,\mathrm d\theta

The limits on \theta and \rho should be obvious. The lower limit on \varphi is obtained by first determining the intersection of the cone and sphere lies in the cylinder x^2+y^2=1. The distance between the central axis of the cone and this intersection is 1. The sphere has radius \sqrt2. Then \varphi satisfies

\sin\varphi=\dfrac1{\sqrt2}\implies\varphi=\dfrac\pi4

(I've added a picture to better demonstrate this)

Computing the integral is trivial. We have

\displaystyle2\pi\left(\int_0^{\sqrt2}\rho^2\,\mathrm d\rho\right)\left(\int_{\pi/4}^\pi\sin\varphi\,\mathrm d\varphi\right)=\boxed{\frac43(1+\sqrt2)\pi}

4 0
3 years ago
Evaluate 13+(43÷2)×5−17 .
inn [45]

Answer:

103.5

Step-by-step explanation:

13 + (43 ÷ 2) × 5 - 17

13 + 21.5 × 5 - 17

13 + 107.5 - 17

107.5 - 4

103.5

5 0
3 years ago
Read 2 more answers
A rectangular tank with a base 4 feet by 5 feet and a height of 4 feet is full of water. The water weighs 62.4 pounds per cubic
posledela

Answer:

(a) 13536.10J

(b) 27072.20J

Step-by-step explanation:

(a) Height of tank (h) = 4 feet = 4/3.2808 = 1.22m

Volume of water in full tank = 4ft×5ft×4ft = 80ft^3

Volume of water in half tank = 1/2 × 80ft^3 = 40ft^3

Density of water = 62.4lb/ft^3

Mass of water = density × volume = 62.4 × 40 = 2496lb = 2496×0.45359kg = 1132.16kg

Work done to empty half of the tank = mgh = 1132.16×9.8×1.22 = 13536.10J

(b) Work done to empty all of the tank = 2 × work done to empty half of the tank= 2 × 13536.10J = 27072.20J

4 0
3 years ago
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