Answer:
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
||Vel_jet_r|| = 465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North
Vel _wind = 35.35 mph East - 35.35 mph North
This means that the resulting velocity of the jet is equal to
Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| = 465.993 mph
Answer:
Exponential Function
Step-by-step explanation:
If you graph the numbers you'll get an exponential function graph. Hope this helps!
Answer:
20π ft³
Step-by-step explanation:
I just did it on the USATestprep
Answer:
Step-by-step explanation:
342.6
x0.28 then multiply them and cont the decimal place so when you get the answer you would move the decimal 3 places to the right
Use angles on straight line add up to 180. Isosceles is all same angle
