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stiks02 [169]
3 years ago
12

Solve for d d= 3r + 120 ;r= 62

Mathematics
2 answers:
Paha777 [63]3 years ago
6 0
D=3(62)+120 is the way to go!
olasank [31]3 years ago
4 0
Equation:d=3(r)+120
If r equals 62, then the r in d=3r+120 would also be 62.
3(r)+120 --> 3(62)+120
186+120
306
d=306
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What is the median and mode
viktelen [127]
Median is the middle number

60, 60, 65, 70, 70, 85, 90

70 is your median

mode is the number(s) that show up the most
60 and 70 is your mode, since they show up twice (one more than the others)

Range is largest number minus the smallest
90 - 60 = 30, 30 is your range

Mean is all the numbers added together divided by the number of numbers there are 
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hope this helps
5 0
3 years ago
Prime factorization of 52​
lara [203]

Answer:

The first prime factor we test is 2:

52 / 2 = 26

26 / 2 = 13

13 is a prime number so the prime factorization is

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Step-by-step explanation:

5 0
3 years ago
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Rewrite the expression by combining like terms. 4x2 - 2x2 + 2y + 6y2 - y + x2​
olasank [31]

Answer:

32 +6y^2+

Step-by-step explanation:

3 0
3 years ago
A cube has a side length of x feet. Which expression represents the surface area of the cube?
alexdok [17]
The answer is D)6x2 square units.

A surface area of a cube is a sum of its sides' areas. A side of the cube is a square, and there are total 6 sides of the cube. Also, an area of the side of the cube is the area of the square, which can be expressed as a², where a is the length of the side. Therefore, the surface area (SA) of the cube is:
SA = 6*a² = 6a²

If side length is x, that means that a = x units.
After replacing it in the formula, you will have:
SA = 6a² = 6x² square units

8 0
4 years ago
Read 2 more answers
A quadrilateral has vertices A(3, 5), B(2, 0), C(7, 0), and D(8, 5). Which statement about the quadrilateral is true? A. ABCD is
Dima020 [189]

Hey There!!

The answer to this is: A quadrilateral has vertices A(3, 5), B(2, 0), C(7, 0), and D(8, 5). Which statement about the quadrilateral is true?" Line BC is parallel to line AD because their slopes is equal i.e. (0 - 0) / (7 - 2) = (5 - 5) / (8 - 3) which gives 0 / 5 = 0 / 5 giving that 0 = 0. We check whether line AB is parallel to line CD. Slope of line AB is given by (0 - 5) / (2 - 3) = -5 / -1 = 5. Slope of line CD is given by (5 - 0) / (8 - 7) = 5 / 1 = 5 We have been able to prove that the opposite sides of the quadrilateral are parallel which means that the quadrilateral is not a trapezoid. Next we check whether the length of the sides are equal. Length of line AB is given by sqrt[(0 - 5)^2 + (2 - 3)^2] = sqrt[(-5)^2 + (-1)^2] = sqrt(25 + 1) = sqrt(26) Length of line BC is given by sqrt[(0 - 0)^2 + (7 - 2)^2] = sqrt[0^2 + 5^2] = sqrt(25) = 5 Length of line CD is given by sqrt[(5 - 0)^2 + (8 - 7)^2] = sqrt[5^2 + 1^2] = sqrt(25 + 1) = sqrt(26) Length of line DA is given by sqrt[(5 - 5)^2 + (8 - 3)^2] = sqrt[0^2 + 5^2] = sqrt(25) = 5 Thus, the length of the sides of the quadrilateral are not equal but opposite sides are equal which means that the quadrilateral is not a rhombus. Finally, we check whether adjacent lines are perpendicular. Recall the for perpendicular lines, the product of their slopes is equal to -1. Slope of line AB = 5 while slope of line BC = 0. The product of their slopes = 5 x 0 = 0 which is not -1, thus the adjacent sides of the quadrilateral are not perpendicular which means that the quadrilateral is not a rectangle. Therefore, ABCD is a parallelogram with non-perpendicular adjacent sides. Thus, For (option A).

Hope It Helped!~ ♡

ItsNobody~ ☆

7 0
4 years ago
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