All categories

3 years ago

34-12 simplest form

Mathematics

1 answer:

BigorU [14]3 years ago

3 0

You start order of operations (PEMDAS)
You multiple left to right and lastly subtract.
12-2=10

You might be interested in

HELP PLS ITS DUE IN A FEW MIN

Tanya [424]

Answer:

S = 50w + 75

Step-by-step explanation:

After each week, Mike gains $50.

Letting w = 0 gives us the amount he started with. In this case, that would be $75.

Therefore, the equation is S = 50w + 75.

5 0

3 years ago

PLLLLLSSSS Heeeellppp ill mark brainliest I promisseeeeeeee plsssss

WARRIOR [948]

Answer:

$2\,(x-1)^2=4$

which is the first option in the list of possible answers.

Step-by-step explanation:

Recall that the minimum of a parabola generated by a quadratic expression is at the vertex of the parabola, and the formula for the vertex of a quadratic of the general form:

$y=ax^2+bx+c$

is at $x_{vertex}=\frac{-b}{2\,a}$

For our case, where $a=2\,\,, b=-4\,\,,\,\,and \,\,c=-2$ we have:

$x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{4}{2\,*\,2}\\x_{vertex}=1$

And when x = 1, the value of "y" is:

$y(x)=2x^2-4x-2\\y(1)=2(1)^2-4(1)-2\\y(1)=2-6\\y(1)=-4\\y_{vertex}=-4$

Recall now that we can write the quadratic in what is called: "vertex form" using the coordinates $(x_{vertex},y_{vertex)$ of the vertex as follows:

$y-y_{vertex}=a\,(x-x_{vertex})^2$

Then, for our case:

$y-(-4)=2\,(x-1)^2\\y=2\,(x-1)^2-4$

Then, for the quadratic equal to zero as requested in the problem, we have:

$y=2\,(x-1)^2-4=0\\2\,(x-1)^2-4=0\\2\,(x-1)^2=4$

5 0

3 years ago

I need help with this question.

lbvjy [14]

0 and 2 are your answers, since the numbers in the table match

4 0

3 years ago

Read 2 more answers

Write 27 + 21 as a product using the GCF as one of the factors.

levacccp [35]

The greatest common factor is 48

8 0

2 years ago

What do you think about geometry?

Brums [2.3K]

Answer:

I think its better than other types of math.

Step-by-step explanation:

7 0

3 years ago

3*4-1*2 simplest form

34-12 simplest form