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3 years ago

The value of the 7 in 27,459 is how many times the value of the 7 in 40,735?

Mathematics

2 answers:

Digiron [165]3 years ago

7 0

Answer:

The answer: 10

alukav5142 [94]3 years ago

4 0

Answer:

Step-by-step explanation:

The 7 in 27,459 is in the thousands place.

The 7 in 40,735 is in the hundreds place.

Any digit in the thousands place has 10 times the value of the same digit in the hundreds place. (The multiplier is 1000, instead of 100.)

_____

In the base-10 number system, each digit location has 10 times the value of the location to its right. The value is determined by the place the digit occupies in the number. That is why it is called a place-value number system.

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What is the difference (2x-3)-(1-1)? O x+2 O x4 Help please!!

AVprozaik [17]

Answer:

I don't know if I understood the question correctly, but this is what I have...

Step-by-step explanation:

If the "x" is a variable:

(2x-3)-(1-1)=

2x-3

If th "x" is a multiplication sign:

(2x-3)-(1-1)=

-6-0=

-6

i hope this helps

7 0

2 years ago

What is the answer to the question?

strojnjashka [21]

Step-by-step explanation:

Since AD bisects BC,

BD = DC.

Therefore 5x - 10 = 3x + 10 and x = 10.

4 0

3 years ago

Read 2 more answers

Construct a polynomial function with the following properties: third degree, only real coefficients, −3 and 3+i are two of the z

irina [24]

Answer:

$\boxed{-3(x+3)(x^2-6x+10)}$

Step-by-step explanation:

Hello,

As the polynomial has only real coefficients, it means that 3-i is a zero too, because we apply the Conjugate Zeros Theorem.

It means that we can write the expression as below, k being a real number that we will have to identify.

$k(x+3)(x-3-i)(x-3+i)=k(x+3)((x-3)^2-i^2)\\\\=k(x+3)(x^2-6x+9+1)\\\\=k(x+3)(x^2-6x+10)$

And for x = 0, y = -90 so we can write

-90=k*3*10, meaning that k=-3

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago

A dog runs from point O to B. The dog reaches A at 2.3 s into the sprint. Then the dog reaches C at 4.1 s. What is the average v

Pavlova-9 [17]

We are given

A dog runs from point O to B

t(OA)=2.3 s

t(OC)=4.1 s

now, we can find time between A and C

t(AC)=t(OC)-t(OA)

t(AC)=4.1-2.3

t(AC)=1.8 s

we are given

distance between A and C is 4m

so,

d=4m

now, we can find average velocity between A and C

$v=\frac{d}{t}$

we can plug values

$v=\frac{4}{1.8}$

$v=2.2m/s$

so, option-C..................Answer

6 0

3 years ago

A(n) = -1/16 (2) ^n-1 what is the 6th term

Anarel [89]

2^5=32
32*(-1/16)=-2
The answer is -2

8 0

3 years ago