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2 years ago

7

The value of the 7 in 27,459 is how many times the value of the 7 in 40,735?

2 answers:

Digiron [165]2 years ago

7 0

Answer:

The answer: 10

alukav5142 [94]2 years ago

4 0

Answer:

10

Step-by-step explanation:

The 7 in 27,459 is in the <em>thousands</em> place.

The 7 in 40,735 is in the <em>hundreds</em> place.

Any digit in the thousands place has 10 times the value of the same digit in the hundreds place. (The multiplier is 1000, instead of 100.)

_____

In the base-10 number system, each digit location has 10 times the value of the location to its right. The value is determined by the place the digit occupies in the number. That is why it is called a place-value number system.

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Substituting
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vlabodo [156]

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Step-by-step explanation:

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2 years ago

When using a ruler, where is the unit?

Afina-wow [57]

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1 year ago

A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len

Gnom [1K]

Answer:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

$df=n-1=93-1=92$

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

$\bar X=5.97$ represent the sample mean for the length

$s=0.4$ represent the sample standard deviation

$n=93$ sample size

$\mu_o =6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:

Null hypothesis: $\mu = 6$

Alternative hypothesis: $\mu \neq 6$

since we don't know the population deviation the statistic is:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing in formula (1) we got:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

P value

The degrees of freedom are given by:

$df=n-1=93-1=92$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0

2 years ago