See the attached picture to better understand the problem
we know that
in the right triangle ABC
tan 48=AC/AB--------> AC=AB*tan 48-----> AC=x*tan 48-----> equation 1
in the right triangle ACD
tan 41=AC/AD-----> AC=AD*tan 41------> AC=(140-x)*tan 41----> equation 2
equate equation 1 and equation 2
x*tan 48=(140-x)*tan 41----> x*tan 48=140*tan 41-x*tan 41
x*[tan 48+tan 41]=140*tan 41
x=140*tan 41/[tan 48+tan 41]-----> x=61.468 m
find AC
AC=x*tan 48-----> AC=61.468*tan 48----> AC=68.27 m----> AC=68 m
the answer is68 m