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2 years ago

A weak base is added to water. Which information is required to find the strength of its conjugate acid?

Chemistry

2 answers:

lozanna [386]2 years ago

5 0

Answer: C) the values of Kb and Kw

Explanation: i just took the test

Otrada [13]2 years ago

4 0

Answer:

The values of Kb and Kw

Explanation:

The conjugated acid would produced when we have the reaction:

$A^- + H_2O~->~HA~+~OH^-$

The equilibrium of this reaction is rule the Kb expression. If we want to solve Ka we have to use the equation:

$Kw~=~Ka*Kb$

Solving for Ka:

$Ka=\frac{Kw}{Kb}$

Therefore we need to know Kw and Kb.

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2 years ago

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Now that Snape and Dumbledore has taught you the finer points of hydration calculations they have a slightly more challenging pr

Mrrafil [7]

Answer:

The value of an integer x in the hydrate is 10.

Explanation:

$Molarity=\frac{Moles}{Volume(L)}$

Molarity of the solution = 0.0366 M

Volume of the solution = 5.00 L

Moles of hydrated sodium carbonate = n

$0.0366 M=\frac{n}{5.00 L}$

$n=0.0366 M\times 5 mol=0.183 mol$

Mass of hydrated sodium carbonate = n= 52.2 g

Molar mass of hydrated sodium carbonate = 106 g/mol+x18 g/mol

$n=\frac{\text{mass of Compound}}{\text{molar mass of compound}}$

$0.183 mol=\frac{52.2 g}{106 g/mol+x\times 18 g/mol}$

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Solving for x, we get:

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The value of an integer x in the hydrate is 10.

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3 years ago

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Rainbow [258]

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2 years ago

Which statements accurately describe mass? Check all that apply.

Alexxandr [17]

Answer:

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3 years ago

What force is necessary to accelerates a 1250kg car at a rate of 40 m/s

zalisa [80]

Answer:

F = 50000 N

Explanation:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m

Given data:

Mass of car = 1250 Kg

Acceleration = 40 m/s².

Force = ?

Solution:

F = m × a

F = 1250 Kg × 40 m/s²

Kg.m/s² = N

F = 50000 N

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2 years ago