pH=2.7
<h3>Further explanation</h3>
Acetic acid = weak acid
![\tt [H^+]=\sqrt{Ka.M}](https://tex.z-dn.net/?f=%5Ctt%20%5BH%5E%2B%5D%3D%5Csqrt%7BKa.M%7D)
Ka = acid ionization constant
M = molarity
Ka for Acetic acid(CH₃COOH) : 1.8 x 10⁻⁵
![\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.222}\\\\=0.001998=1.998\times 10^{-3}](https://tex.z-dn.net/?f=%5Ctt%20%5BH%5E%2B%5D%3D%5Csqrt%7B1.8%5Ctimes%2010%5E%7B-5%7D%5Ctimes%200.222%7D%5C%5C%5C%5C%3D0.001998%3D1.998%5Ctimes%2010%5E%7B-3%7D)
Mixing a base with an acid results in a chemical reaction called neutralization.<span> The result is a perfectly balanced solution of salt and water with a pH of 7 if the acid and base are balanced properly. Depending on the bases and acids used, it can be a dangerous experiment.
Hope I helped you lots!! :3</span>
Answer:
C) K
Explanation:
K has an electron configuration of 2.8.8.1
Here we have to choose the correct statement behind the polarity of the water molecule.
The polarity of the water molecules is due to the B. deflection of the hydrogen atoms by the lone pair of electrons.
The bonding of the water (H₂O) molecule is shown in the figure. There remain two lone pair of electrons on the oxygen atom. The oxygen atom has 6 valence electrons among which 2 are involved to make the covalent bond with two hydrogen atom.
The lone pair if electrons exerted lone pair-bond pair repulsion and H₂O has a bent structure as shown in the figure. In this way the dipole moment generated by oxygen and hydrogen cannot be nullified and it has a permanent dipole moment which leads the molecule to be polar in nature.
The water molecule is not linear in nature it has bent structure.
There is a huge difference of electronegativity between the hydrogen (H) and oxygen (O) atom. The oxygen atom is highly electronegative whereas the hydrogen atom is electropositive in nature.
The hydrogen bond formation is due to the fact the molecule is polar in nature.
Answer:
Molality of solution=10.11 m
Explanation:
We are given that
Given mass of KCl(WB)=75.3 g
Given mass of water (WA)=100 g=100/1000=0.1 kg
1 kg=1000 g
Molar mass of H=1.01 g
Molar mass of K=39g
Molar mass of Cl=35.45 g
We have to find the molality of a solution.
Molar mass of KCl(MB)=39+35.45
Molar mass of KCl(MB) =74.45 g
Number of moles of solute (KCl)=
Number of moles of solute (KCl)=
Number of moles of solute (KCl)=1.011 moles
Molality of solution
=
Using the formula
Molality of solution=
Molality of solution=10.11 m
