Answer:
Explanation:
Let us first take a look at the image below;
In the acid - base reaction; we can see the transfer of electrons that takes place;
We can also see that the reaction goes in the direction which converts the stronger acid and the stronger base to the weaker acid and the weaker base.
The stronger acid is shown with the one with more negative 
Value.
∴ The equilibrium constant for the acid-base reaction is expressed as:
From Value (shown in the image below), it is clear and vivid that hydrobromic acid is a stronger acid than the ethyloxonium ion, therefore the equilibrium lies to the right.
From the chemical equation (shown in the attached image); the equilibrium constant for the acid-base reaction can be expressed as:
Second law of thermodynamics states entropy of the universe is always increasing. entropy always increases in a spontaneous process .
option B) second law of thermodynamics
for example if we keep a hot cup of coffee the heat is lost to surrounding and entropy( randomness increases) since it is a natural process entropy of universe increases.
The compound contains an ester functional group.
An ester is a carbonyl (C=O) group with an alkyl (R) group on one side and an alkoxy (OR) group on the other.
We write the <em>condensed structural formula</em> of an ester as R(C=O)OR or RCOOR.
3 atoms! Glad I can help! :)
<h3>
Answer:</h3>
= 5.79 × 10^19 molecules
<h3>
Explanation:</h3>
The molar mass of the compound is 312 g/mol
Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)
We are required to calculate the number of molecules present
We will use the following steps;
<h3>Step 1: Calculate the number of moles of the compound </h3>
Therefore;
Moles of the compound will be;
= 9.615 × 10⁻5 mole
<h3>Step 2: Calculate the number of molecules present </h3>
Using the Avogadro's constant, 6.022 × 10^23
1 mole of a compound contains 6.022 × 10^23 molecules
Therefore;
9.615 × 10⁻5 moles of the compound will have ;
= 9.615 × 10⁻5 moles × 6.022 × 10^23 molecules
= 5.79 × 10^19 molecules
Therefore the compound contains 5.79 × 10^19 molecules
