Answer:
2.28 g of CsF.
Explanation:
The following data were obtained from the question:
Molar mass of CsF = 151.9 g/mol.
Volume = 300 mL
Molarity of CsF = 0.05 M
Mass of CsF =.?
Next, we shall convert 300 mL to litre (L). This can be obtained as follow:
1000 mL = 1 L
Therefore,
300 mL = 300 mL /1000 mL × 1 L
300 mL = 0.3 L
Therefore, 300 mL is equivalent to 0.3 L
Next, we shall determine the number of mole CsF in the solution. This can be obtained as follow:
Volume = 0.3 L
Molarity of CsF = 0.05 M
Mole of CsF =.?
Molarity = mole /Volume
0.05 = mole of CsF /0.3
Cross multiply
Mole of CsF = 0.05 × 0.3
Mole of CsF = 0.015 mole.
Finally, we shall determine the mass of CsF needed to prepare the solution as follow:
Mole of CsF = 0.015 mole.
Molar mass of CsF = 151.9 g/mol.
Mass of CsF =.?
Mole = mass /Molar mass
0.015 = mass of CsF /151.9
Cross multiply
Mass of CsF = 0.015 × 151.9
Mass of CsF = 2.28 g
Therefore, 2.28 g of CsF is needed to prepare the solution.
