Answer: D. Series circuits are simpler than parallel circuits.
Explanation:
In series circuit, all the components are connected in single path of current flow.
If one part of the circuit breaks, complete circuit would break and all the other parts also would not operate.
The voltage is not same everywhere. It is different across each component.
In series circuit, net resistance is more as resistance of all the components connected in series are added up.
So, the only advantage of a series circuit is that is simpler than the parallel circuits. Thus, the correct option is D.
Answer:
82.59 m/s or 297.324 km/h
Explanation:
From the question,
Applying
V = √[2(P'/ρ)].................. Equation 1 ( From
Where V = Speed of the aircraft, Differential Pressure of the air craft, ρ = Density of air at an altitude of 3000 m.
Given: P' = 3100 N/m², ρ = 0.909 kg/m³
Substitute into equation 1
V = √[2(3100/0.909)]
V = √(2×3410.34)
V = √(6820.68)
V = 82.59 m/s
V = 297.324 km/h
Hence the speed of the aircraft is 82.59 m/s or 297.324 km/h
The quantity of carbon tetrachloride, CCl₄ she will use to make her conversion is molar mass
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass
<h3>How to determine the mole of CCl₄</h3>
- Mass of CCl₄ = 30 g
- Molar mass of CCl₄ = 12 + (35.5×4) = 154 g/mol
- Mole of CCl₄ =?
Mole = mass / molar mass
Mole of CCl₄ = 150 / 154
Mole of CCl₄ = 0.974 mole
Thus, we can see that the molar mass of CCl₄ is needed to obtain the number of mole.
Learn more about mole:
brainly.com/question/13314627
#SPJ4
Answer:
Non-zero digits are always significant.
Any zeros between two significant digits are significant.
A final zero or trailing zeros in the decimal portion ONLY are significant. If a number ends in zeros to the right of the decimal point, those zeros are significant.
Explanation:
1.138 has 4 significant figures, which are 1, 1, 3 and 8. The numbers after the decimal point are decimals and are significant figures.
