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shutvik [7]
3 years ago
6

Which salt is not formed from metal ions. NaCl, BaSO4, SrCl2, NH4OH

Chemistry
2 answers:
Novay_Z [31]3 years ago
6 0

NaCl is correct answer of your question

Allisa [31]3 years ago
4 0

Answer:

NH4OH

Explanation:

BCOZ IT IS PRESENT IN 15th GROUO WHICH NON METAL

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Which type of bond will most likely be found in HBr?
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<span>HBr is covalent bond.!

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6 0
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What evidence suggests that four-legged animals came from fish?
cupoosta [38]

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Paleontologists have uncovered new fossils from Tiktaalik roseae, which, while still a fish, is considered a transitional fossil that also has traits common to the first four-footed animals. This more complete picture of Tiktaalik suggests that the creature had strong, mobile hind fins.

Explanation:

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3 years ago
Durante una determinación de acidez en una muestra contaminada, agregas como indicador fenolftaleina y torno a violeta. ¿Qué sus
algol13

Answer:

HCl, ya que la sustancia es una base que se debe titular con un ácido.

Explanation:

¡Hola!

En este caso, teniendo en cuenta la descripción inicial de la sustancia, la cual se torna violeta cuando se le agrega la fenolftaleína, es posible inderir que esta sustancia es una base con pH básico. Ahora bien, en torno a la especificación de un proceso de titulación, es claro que dicha base debe ser titulada con un ácido, y este caso, con HCl, ácido chlorhídrico, con el fin the alcanzar el punto de equivalencia.

¡Saludos!

6 0
3 years ago
3S8 + 8 OH- + 8 S3 + 4 HOOH
NemiM [27]

Answer:

Second order

Explanation:

We could obtain the order of reaction by looking at the table very closely.

Now notice that in experiment 1 and 2, the concentration of [OH^-] was held constant while the concentration of [S8] was varied.  So we have;

a situation in which the rate of reaction was tripled;

0.3/0.1 = 2.10/0.699

3^1 = 3^1

Therefore the order of reaction with respect to  [S8] is 1.

For [OH^-], we have to look at experiment 2 and 3 where the concentration of [S8] was held constant;

x/0.01 = 4.19/2.10

x/0.01 = 2

x = 2 * 0.01

x = 0.02

So we have;

0.02/0.01 = 2^1

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The order of reaction with respect to  [OH^-] = 1

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Rate = k[S8]^1  [OH^-] ^1

Overall order of reaction = 1 + 1 = 2

Therefore the reaction is second order.

4 0
3 years ago
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