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prisoha [69]
3 years ago
5

What are the groundwater labels?

Chemistry
1 answer:
Sergio [31]3 years ago
7 0

<span>Acetochlor demonstrates characteristics associated with chemicals that have been detected in groundwater. To protect groundwater from contamination, acetochlor product labels restrict the use of acetochlor on porous soils over shallow groundwater:</span>
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Consider a general reaction A ( aq ) enzyme ⇌ B ( aq ) A(aq)⇌enzymeB(aq) The Δ G ° ′ ΔG°′ of the reaction is − 5.980 kJ ⋅ mol −
Grace [21]

Answer : The value of K_{eq} is, 11.2

The value of \Delta G_{rxn} is -9.04 kJ/mol

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy  = -5.980 kJ/mol = -5980 J/mol

R = gas constant = 8.314 J/K.mol

T = temperature = 25^oC=273+25=298K

K_{eq}  = equilibrium constant  = ?

Now put all the given values in the above formula, we get:

\Delta G^o=-RT\times \ln K_{eq}

-5980J/mol=-(8.314J/K.mol)\times (298K)\times \ln K_{eq}

K_{eq}=11.2

Thus, the value of K_{eq} is, 11.2

Now we have to calculate the \Delta G_{rxn}.

The formula used for \Delta G_{rxn} is:

The given reaction is:

A(aq)\rightleftharpoons B(aq)

\Delta G_{rxn}=\Delta G^o+RT\ln Q

\Delta G_{rxn}=\Delta G^o+RT\ln \frac{[B]}{[A]}    ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction  = ?

\Delta G_^o =  standard Gibbs free energy  = -30.5 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 37.0^oC=273+37.0=310K

Q = reaction quotient

[A] = concentration of A = 1.8 M

[B] = concentration of B = 0.55 M

Now put all the given values in the above formula 1, we get:

\Delta G_{rxn}=(-5980J/mol)+[(8.314J/mole.K)\times (310K)\times \ln (\frac{0.55}{1.8})

\Delta G_{rxn}=-9035.75J/mol=-9.04kJ/mol

Therefore, the value of \Delta G_{rxn} is -9.04 kJ/mol

3 0
3 years ago
Cuales son los numeros cuanticos con ejemplo
ra1l [238]

Puede tomar los valores enteros positivos: n= 1, 2, 3, 4, 5, 6, 7. Por ejemplo si tengo un elemento químico que su último nivel es el 3s, su número cuántico principal sería el 3. Si tengo un elemento químico en que su último nivel es el 1s, entonces su número cuántico principal sería 1.
4 0
3 years ago
If 30.0 ml of 0.150 m aqueous sodium hydroxide is mixed with 30.0 ml of 0.150 m aqueous hydrochloric acid in a calorimeter at an
umka21 [38]
Answer : As given in the question the concentration of acid and base are in equimolar proportion so,

the simple net ionic reaction that the system is undergoing can be given as,
H^{+}  _{(aq.)}   +  OH^{-} _{(aq.)} ----\ \textgreater \  H_{2} O +  heat

we can now calculate the total number of moles reacting in the species as,

(30 mL) X (1L/1000ML) X 0.150 moles = 4.5 X 10 ^{-3} moles.

Now, we know the specific heat of water as 4.186 J/g °C.

Now considering the total volume of the product as 60 mL or 60 g (as it is water it can be g or mL) hence, ΔC is 2.5 C.

Now converting these into joules = 4.186 J/g °C X 2.5 X 60 = 627.9 Joules.

On dividing this we get 627.9 Joules / 4.5 X 10 ^{-3} moles = 140 KiloJoules/mole.

So the answer is 140 KJ/M.
3 0
3 years ago
If 6 electrons are available to fill five empty 6d atomic orbitals, how will the electrons be distributed in the five orbitals?
Leokris [45]

Answer:

Option C

Explanation:

According to Hund's rule

  • pairing of electrons occur first in lower energy orbitals then in orbitals having higher energy.

d subshell has 5 orbitals.

  • so first these 5 get filled.
  • The. one will be added to first one.
7 0
3 years ago
If 4 moles of gas are added to a container that already holds 1 mole of gas, the pressure inside the container _____ due to the
sveticcg [70]

Answer: will be five times higher

If 4 moles of gas are added to a container that already holds 1 mole of gas, the pressure inside the container

will be five times higher due to the change in the amount of gas.

Explanation:

4 moles of gas + 1 mole of gas = 5 moles of gas.

Also, the ideal gas equation pV = nRT

show that pressure is directly proportional to number of moles; so, if 1 mole of gas contains molecules that move randomly and freely under pressure inside the container; addition of 4 extra moles will sum up to 5moles of gas molecules moving randomly under pressure, and that is five times higher as well.

4 0
3 years ago
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