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Setler [38]
3 years ago
9

A molecule has sp2 hybridization with 1 lone pair.... The electron pair geometry of this molecule is: ... The geometry of this m

olecule is: .... This molecule will have an approximate bond angle of:
Chemistry
1 answer:
MrRa [10]3 years ago
6 0

Answer:

The electron pair geometry is Trigonal planar

Molecular geometry - Bent

Approximate bond angle - <120°

Explanation:

The valence shell electron pair repulsion theory enables us to predict the shapes of molecules based on the number of electron pairs present on the valence shell of the central atom and based on the hybridization state of the central atom.

sp2 hybridization corresponds to trigonal planar geometry. Let us recall that the presence of lone pairs causes a deviation of the molecular geometry from the expected geometry based on the number of electron pairs.

Hence, owing to one lone pair present, the observed molecular geometry is bent.

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A first order reaction has rate constants of 4.6 x 10-2 s-1 and 8.1 x 10-2 s-1 at 0ºC and 20ºC, respectively. What is the value
Airida [17]

Answer:

D.  18,800 J/mol

Explanation:

We need to use the Arrhenius equation to solve for this problem:

k=Ae^{\frac{-E_a}{RT}, where k is the rate constant, A is the frequency factor, E_a is the activation energy, R is the gas constant, and T is the temperature in Kelvins.

We want to find the value of E_a, so let's plug some of the information we have into the equation. The gas constant we can use here is 8.31 J/mol-K.

At 0°C, which is 0 + 273 = 273 Kelvins, the rate constant k is 4.6*10^{-2}. So:

k=Ae^{\frac{-E_a}{RT}

4.6*10^{-2}=Ae^{\frac{-E_a}{8.31*273}

At 20°C, which is 20 + 273 = 293 Kelvins, the rate constant k is 8.1*10^{-2}. So:

k=Ae^{\frac{-E_a}{RT}

8.1*10^{-2}=Ae^{\frac{-E_a}{8.31*293}

We now have two equations and two variables to solve for. We just want to find Ea, so let's write the first equation for A in terms of Ea:

4.6*10^{-2}=Ae^{\frac{-E_a}{8.31*273}

A=\frac{4.6*10^{-2}}{e^{\frac{-E_a}{8.31*273}} }

Plug this in for A in the second equation:

8.1*10^{-2}=Ae^{\frac{-E_a}{8.31*293}

8.1*10^{-2}=\frac{4.6*10^{-2}}{e^{\frac{-E_a}{8.31*273}} }e^{\frac{-E_a}{8.31*293}

After some troublesome manipulation, the answer should come down to be approximately:

Ea = 18,800 J/mol

The answer is thus D.

5 0
3 years ago
How many different principal quantum numbers can be found in the ground-state electron configuration of nickel?A) 2.B) 3.C) 4.D)
Naddik [55]

Answer:

C) 4.

Explanation:

Hello!

In this case, since the electron configuration of nickel at its ground-state, considering 28 as its atomic number and the number of electrons it has in one atom, is:

Ni^{28}:1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^8

We can see it has four energy levels, 1, 2, 3 and 4, which are related to the following principal quantum number, that describes the energy of an electron in the atom and its most probable distance with respect to the nucleus.

Therefore, nickel has C) 4 different principal quantum numbers.

Best regards!

5 0
3 years ago
What is the frequency of an x-Ray with a wavelength of 1.15 times 10^-10
Bezzdna [24]
V = f 入 (velocity = frequency x wavelength) 
<span>If we have the speed ( for wave in vacuum </span><span>i.e. 3 x 10^8 m/s) </span>
<span>Then the frequency of x-ray is </span>
<span>(3 x 10^8) ÷(1.15 x 10^-10) = 2.61 x 10^18 </span>
3 0
3 years ago
How many neutrons are in the nucleus of an atom with an atomic number of 25
Makovka662 [10]

Answer:

The neutron is 30

Explanation:

The element with atomic number of 25 is Manganese. it has a mass number of approximately 55.

Therefore, the neutron number = Mass number - Proton number (i.e. atomic number)

                                         = 55 - 25

  Neutron number            = 30

4 0
3 years ago
Pick the TWO true statements from the following: Graduated cylinders are used to measure volume. All graduated cylinders measure
snow_lady [41]
- <span>Graduated cylinders are used to measure volume.
- </span><span>Always read a graduated cylinder from the bottom of the meniscus.</span>
5 0
3 years ago
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