Decomposition using water polymerization
Answer:
The protic solvents are (CH3)2CHOH, NH3, and HCONH2
The aprotic solvent are CH3NO2, CH2Cl2, and N(CH3)3
Explanation:
A protic solvent is a solvent that has a hydrogen atom bound to an oxygen (O), a nitrogen (N), or fluoride (F). Generally, any solvent that contains a labile H⁺ is called a protic solvent.
a. (CH3)2CHOH
(CH3)2CHOH is a protic solvent because one of the hydrogens is bound to oxygen (O)
b. CH3NO2
CH3NO2 is an aprotic (i.e not a protic solvent) solvent because all the hydrogens are bound to carbon.
c. CH2Cl2
CH2Cl2 is an aprotic solvent because all the hydrogens are bound to carbon.
d. NH3 is a protic solvent because all the hydrogens are bound to Nitrogen (N)
e. N(CH3)3 is an aprotic solvent because all the hydrogens are bound to carbon
f. HCONH2 is a protic solvent because two of the hydrogens are bound to Nitrogen (N)
The molarity of the solution will be 4.97 M.
<h3>What is molarity?</h3>
It is the number of moles of solutes per 1 liter of solvent or solution.
Mole of 34.1 g NaCl = 34.1/58.44 = 0.5835 mol
117.3 mL = 117.3/1000 = 0.1173 L
Molarity of the solution = 0.5835/0.1173 = 4.97 M
More on molarity can be found here: brainly.com/question/2817451
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Answer:
This is because of diffusion , the movement of particles from an area of high concentration to an area of low concentration. ... This means that diffusion does not happen in solids – the particles in a solid can only vibrate and cannot move from place to place.
Answer:
A) when the titration is nearing the end point in titration the color of the solution starts to change and the change in color does not disappear as fast as it was during the beginning of the titration
B) The volume of NaOH required to permanently change the indicator at the end point is a drop of NaOH
c) The volume required by samples #2 and #3 will be the same i.e 19.90 mL of NaOH, if the concentration of KHP base used for the samples are the same
D) The volume required by samples #2 and #3 will be the same i.e 29.05 mL OF NaOH, if the concentration of Vinegar and base for the samples are the same
Explanation:
A) when the titration is nearing the end point in titration the color of the solution starts to change and the change in color does not disappear as fast as it was during the beginning of the titration
B) The volume of NaOH required to permanently change the indicator at the end point is a drop of NaOH
c) The volume required by samples #2 and #3 will be the same i.e 19.90 mL of NaOH, if the concentration of KHP base used for the samples are the same
D) The volume required by samples #2 and #3 will be the same i.e 29.05 mL OF NaOH, if the concentration of Vinegar and base for the samples are the same