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svp [43]
3 years ago
15

Making homemade ice cream is one of life's great pleasures. fresh milk and cream, sugar, and flavorings are churned in a bucket

suspended in an ice–water mixture, the freezing point of which has been lowered by adding rock salt. one manufacturer of home ice cream freezers recommends adding 2.50 lb (1130 g) of rock salt (nacl) to 16.0 lb of ice (7250 g) in a 4-qt freezer. calculate the weight percent of nacl of the solution that will result when this mixture melts.
Chemistry
2 answers:
vampirchik [111]3 years ago
6 0

We know that weight percent can be calculated as

weightpercent=\frac{weight-of-substanceX100}{totalweight}

total weight = weight of NaCl + weight of water

weight of NaCl = 1130 g

weight of water = 7250 g

total weight = 1130 + 7250 = 8380g

Therefore

weight % of NaCl = \frac{1130X100}{1130+7250}=13.48%

Thus weight % = 13.48 %

crimeas [40]3 years ago
4 0
It should be 13.48%.

 1130g NaCL/7250g Ice + 1130 NaCl=0.1348 x 100%= 13.48%
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Kp for the following reaction is 0.16 at 25 degree C. 2 NOBr(g) 2 NO(g) Br_2(g) The enthalpy change for the reaction at standard
finlep [7]

Answer:

Explanation:

Given that:

2 NOBr_{(g)} \iff 2 NO_{(g)} + Br_{2(g)}

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3 years ago
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Aliun [14]
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1) LiF smaller  cation then KF
1,036                                 <span>853
</span><span>The lattice energy increases as cations get smaller, as shown by LiF and KF.
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2) The same cation Li , so wrong statement.

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4) NaCl smaller cation then KF
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7 0
3 years ago
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Answer:

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Explanation:

6 0
3 years ago
How much heat is required to raise the temperature of 670g of water from 25.7"C to 66,0°C? The specific heat
inna [77]

Answer:

Explanation:

q= mc theta

where,

Q = heat gained

m = mass of the substance = 670g

c = heat capacity of water= 4.1 J/g°C    

theta =Change in temperature=( 66-25.7)

Now put all the given values in the above formula, we get the amount of heat needed.

q= mctheta

q=670*4.1*(66-25.7)

  =670*4.1*40.3

=110704.1

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3 years ago
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