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svp [43]
3 years ago
15

Making homemade ice cream is one of life's great pleasures. fresh milk and cream, sugar, and flavorings are churned in a bucket

suspended in an ice–water mixture, the freezing point of which has been lowered by adding rock salt. one manufacturer of home ice cream freezers recommends adding 2.50 lb (1130 g) of rock salt (nacl) to 16.0 lb of ice (7250 g) in a 4-qt freezer. calculate the weight percent of nacl of the solution that will result when this mixture melts.
Chemistry
2 answers:
vampirchik [111]3 years ago
6 0

We know that weight percent can be calculated as

weightpercent=\frac{weight-of-substanceX100}{totalweight}

total weight = weight of NaCl + weight of water

weight of NaCl = 1130 g

weight of water = 7250 g

total weight = 1130 + 7250 = 8380g

Therefore

weight % of NaCl = \frac{1130X100}{1130+7250}=13.48%

Thus weight % = 13.48 %

crimeas [40]3 years ago
4 0
It should be 13.48%.

 1130g NaCL/7250g Ice + 1130 NaCl=0.1348 x 100%= 13.48%
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Musya8 [376]

Answer:

The value of K_p is 0.02495.

Explanation:

Initial concentration of SCL_2 gas = 0.675 M

Initial concentration of C_2H_4 gas = 0.973 M

Equilibrium concentration of mustard gas = 0.35 M

SCl_2 (g) + 2 C_2H_4 (g)\rightleftharpoons S(CH_2CH_2Cl)_2(g)

initially

0.675 M            0.973 M        0

At equilibrium ;

(0.675-0.35) M            (0.973-2 × 0.35) M        0.35 M

The equilibrium constant is given as :

K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}

=\frac{0.35 M}{(0.675-0.35) M\times ((0.973-2 × 0.35) M)^2}

K_c=14.45

The relation between K_p and K_c are :

K_p=K_c\times (RT)^{\Delta n}

where,

K_p = equilibrium constant at constant pressure = ?

K_c = equilibrium concentration constant =14.45

R = gas constant = 0.0821 L⋅atm/(K⋅mol)

T = temperature = 20.0°C =20.0 +273.15 K=293.15 K

\Delta n = change in the number of moles of gas = [(1) - (1 + 2)]=-2

Now put all the given values in the above relation, we get:

K_p=14.45\times (0.0821L.atm/K.mol\times 293.15 K)^{-2}

K_p=6.2\times 10^{4}

K_p=0.02495

The value of K_p is 0.02495.

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