A sequence can be generated by using fn = 2f(n-1)+1, where f1 = 4 and n is a whole number greater than 1. What are the first fou r terms in the sequence?
1 answer:
Answer:
<em>{9,19,39,79}</em>
Step-by-step explanation:
<u>Recursive Sequences</u>
The recursive sequence can be identified because each term is given as a function of one or more of the previous terms. Being n an integer greater than 1, then:
f(n) = 2f(n-1)+1
f(1) = 4
To find the first four terms of the sequence, we set n to the values {2,3,4,5}
f(2) = 2f(1)+1
Since f(1)=4:
f(2) = 2*4+1
f(2) = 9
f(3) = 2f(2)+1
Since f(2)=9:
f(3) = 2*9+1
f(3) = 19
f(4) = 2f(3)+1
Since f(3)=19:
f(4) = 2*19+1
f(4) = 39
f(5) = 2f(4)+1
Since f(4)=39:
f(5) = 2*39+1
f(5) = 79
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