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e-lub [12.9K]
3 years ago
8

A sequence can be generated by using fn = 2f(n-1)+1, where f1 = 4 and n is a whole number greater than 1. What are the first fou

r terms in the sequence?
Mathematics
1 answer:
hoa [83]3 years ago
4 0

Answer:

<em>{9,19,39,79}</em>

Step-by-step explanation:

<u>Recursive Sequences</u>

The recursive sequence can be identified because each term is given as a function of one or more of the previous terms. Being n an integer greater than 1, then:

f(n) = 2f(n-1)+1

f(1) = 4

To find the first four terms of the sequence, we set n to the values {2,3,4,5}

  • For n=2

f(2) = 2f(1)+1

Since f(1)=4:

f(2) = 2*4+1

f(2) = 9

  • For n=3

f(3) = 2f(2)+1

Since f(2)=9:

f(3) = 2*9+1

f(3) = 19

  • For n=4

f(4) = 2f(3)+1

Since f(3)=19:

f(4) = 2*19+1

f(4) = 39

  • For n=5

f(5) = 2f(4)+1

Since f(4)=39:

f(5) = 2*39+1

f(5) = 79

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Answer:

\sf \Bigg[ \frac{ ( - 4 \times ( - 3)) }{2} \Bigg] \: and  \: \Bigg[ \frac{ - ( - 5 \times 8)}{10} + 2 \Bigg]

Step-by-step explanation:

Given:

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To find:

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Expression first,

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<em>Verification,</em>

\frac{ ( - 4 \times ( - 3))  }{2} =  \frac{12}{2}   = \cancel\frac{12}{2} = 6

Expression second,

Using numbers 10,8,2,-5

aligning the above numbers as,

\frac{ - ( - 5 \times 8)}{10} + 2

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<em>Verification</em>

\frac{ - ( - 5 \times 8)}{10} + 2 =  \frac{ 40}{10}  + 2   \\ \\ \frac{ - ( - 5 \times 8)}{10} + 2= 4 + 2 \\  \\\frac{ - ( - 5 \times 8)}{10} + 2  = 6

<em><u>Thanks for joining brainly community!</u></em>

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