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3 years ago

The SI unit for speed is a. m. b. m/s. c. m/s². d. m/s west.

1 answer:

7 0

Speed = Distance / Time

SI unit for Distance is meters, m, and for time is seconds, s,

Speed = Distance / Time = m/s

Option b.

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12. If 5t + 2 = 6, then t =

tankabanditka [31]

It would be t=0.8, mainly bc you subtract two from six , that reduces it to four
then you divide four by five and it should give you your answer
and to chack your work put .8 where t was and solve

6 0

3 years ago

Read 2 more answers

3) g(n) = 2n<br> h(n) = n² + 5<br> Find (g + h)(n)

elena55 [62]

(g + h)(n) =
g(n) + h(n) =
2n + n^2 + 5 =
n^2 + 2n + 5 (standard form)

6 0

2 years ago

Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal

a_sh-v [17]

Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

$\dfrac{1}{x}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{1}{y + 49}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{y + 49 + y}{y^{2} + 49 y }$ = $\dfrac{1}{49}$

Or, 2 y + 49 = $\dfrac{y^{2}+49y }{19}$

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = $\frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, y = $\frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}$

Or, y = $\frac{- 1 \pm \sqrt{121+3724}}{2}$

or, y = $\frac{- 1 \pm \sqrt{3845}}{2}$

or, y = $\frac{- 1 \pm 62.008}{2}$

∴ y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0

3 years ago

find 3 consecutive numbers such that twice the greatest added to three times the least amount of 34.

Ket [755]

Answer:

Step-by-step explanation:

2(x+2) + 3x

2x + 4 + 3x = 34

5x + 4 = 34

5x = 34–4

5x = 30

x = 30/5

x = 6

6 0

2 years ago

Find the value of the unique real number theta between 0 and 2pi that satisfies the given conditions.

romanna [79]

135 and 225

Explanation: This one is very hard for me to explain sorry

Mark brainliest please

3 0

3 years ago