Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
= (cos^2x/sin^2x) { sin^2x }
= cos^2x
Note that
sin(x + y) = sin(x) cos(y) + cos(x) sin(y).
Therefore by setting x = π/2 and y = π/7, obtain
sin(π/2 + π/7) = sin(π/2)*cos(π/7) + cos(π/2)*sin(π/7)
The right side is what we want to evaluate. It is equal to
sin(π/2 + π/7) = sin (9/14)π
Answer:
We need to compute for the length of each trophy given that one trophy is 5 inches wider than the other.
Let x be the length of the first trophy.
Let x+5 be the length of the second trophy
The solution is shown below:
x + (x + 5) = 17
x + x + 5 =17
2x =17 -5
2x = 12
x = 12/2
x=6 (for the first trophy)
x + 5 = 6+5 = 11 (for the second trophy)
The first trophy is 6 inches wide while the second trophy is 11 inches wide.
Answer: umm I think the best estimate would be$37.38
Step-by-step explanation: