Rearrange to
6ab+21b-8a-28 now factor 1st and 2nd pair of terms...
3b(2a+7)-4(2a+7)
(3b-4)(2a+7)
So it is the third one down...
Answer:
\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]
Step-by-step explanation:
Given is a matrix 3x3 as
![\left[\begin{array}{ccc}1&0&2\\-3&1&4\\2&-3&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%262%5C%5C-3%261%264%5C%5C2%26-3%264%5Cend%7Barray%7D%5Cright%5D)
|A| =2 hence inverse exists.
Cofactors are 16 20 7
6 8 3
2 2 1
Hence inverse =
![\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%266%262%5C%5C20%268%262%5C%5C7%263%261%5Cend%7Barray%7D%5Cright%5D)
Answer:
67500
Step-by-step explanation:
4-----54000
5-----x
4x=54000*5
x=67500