Answer: True
Solution:
Rearrange the equation to the LHS:
[x^2 + 8x + 16] · [x^2 – 8x + 16] - (x^2 – 16)^2 = 0
Factoring x^2+8x+16
x^2 - 4x - 4x - 16
= (x-4) • (x-4)
= = (x+4)2
So now we have an equation
(x + 4)^2 • (x - 4)^2 - (x^2 - 16)^2 = 0
Step 2: Evaluate the following:
(x+4)2 = x^2+8x+16
(x-4)2 = x^2-8x+16
(x^2-16)2 = x^4-32x^2+256
(x^2+8x+16) (x^2-8x+16 ) - (x^4-32x^2+256 )
0 = 0
Hence True
<u>Part 1</u>
<u />
We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus, the domain is 
<u>Part 2</u>
<u />
We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus,

Thus, the domain in interval notation is 
Answer:
-4
Step-by-step explanation:
(4-2)³ = 8
so 8 - 3 x 4
is equal to -4
Answer:
139
Step-by-step explanation:
57+67+45=169÷3=139