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Nana76 [90]
3 years ago
12

Please help me with this. Method included please

Mathematics
2 answers:
marshall27 [118]3 years ago
5 0
I got the same and the were right hope they were right for you to
Ilya [14]3 years ago
4 0

Answer:

a) 9.135

b) 392.79

Step-by-step explanation:

Hope my answers are helpful

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Suppose that a manager is interested in estimating the average amount of money customers spend in her store. After sampling 36 t
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Answer: The managers statment would most likely give the valid interpretation.

Step-by-step explanation: If the store manager is 95% confident that the average amount spent was between $31.84 and $38.66. Then the store manager is most likey correct so I would have to say I agree with the manager. This may be a tricky question at first, but look at the problem from a different perspective. I am very sorry if this happens to be wrong.

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3 years ago
A bank sends its customers an email when their accounts fall below —$1. Which inequality models this situation?
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Answer:

a bank sends its customers an email iff a<1

Step-by-step explanation:

Let a=account

So, a<1

Therefore, a bank sends its customers an email iff a<1

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3 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
27x39 Plz help jk jk
lesya [120]

Answer: 1053

Step-by-step explanation: ...............................

8 0
2 years ago
Coffee company wants to make sure that their coffee is being served at the right temperature. If it is too hot, the customers co
andrey2020 [161]

Answer:

The average temperature of coffee in the sample, which is 70.2.

Step-by-step explanation:

The population is all the costumers. The company has determined that they want the average coffee temperature to be 65 degrees C. So, 65 degrees C is the average of the population.

The sample is the 20 orders. The mean \mu of the sample is 70.2C(That is, the mean of the 20 orders0. So, the correct answer is:

The average temperature of coffee in the sample, which is 70.2.

3 0
3 years ago
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