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3 years ago

Please help me with this. Method included please

Mathematics

2 answers:

marshall27 [118]3 years ago

5 0

I got the same and the were right hope they were right for you to

Ilya [14]3 years ago

4 0

Answer:

a) 9.135

b) 392.79

Step-by-step explanation:

Hope my answers are helpful

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Suppose that a manager is interested in estimating the average amount of money customers spend in her store. After sampling 36 t

Kitty [74]

Answer: The managers statment would most likely give the valid interpretation.

Step-by-step explanation: If the store manager is 95% confident that the average amount spent was between $31.84 and $38.66. Then the store manager is most likey correct so I would have to say I agree with the manager. This may be a tricky question at first, but look at the problem from a different perspective. I am very sorry if this happens to be wrong.

4 0

3 years ago

A bank sends its customers an email when their accounts fall below —$1. Which inequality models this situation?

Semenov [28]

Answer:

a bank sends its customers an email iff a<1

Step-by-step explanation:

Let a=account

So, a<1

Therefore, a bank sends its customers an email iff a<1

6 0

3 years ago

Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th

Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 21-1 = 20$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have $T = 2.528$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{0.40}{\sqrt{21}} = 0.0873$

Now, we multiply T and s

$M = 2.528*0.0873 = 0.2207$

Then

The lower end of the interval is the mean subtracted by M. So:

$L = 3.27 - 0.2207 = 3.0493$

The upper end of the interval is the mean added to M. So:

$LCL = 3.27 + 0.2207 = 3.4907$

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0

3 years ago

27x39 Plz help jk jk

lesya [120]

Answer: 1053

Step-by-step explanation: ...............................

8 0

2 years ago

Coffee company wants to make sure that their coffee is being served at the right temperature. If it is too hot, the customers co

andrey2020 [161]

Answer:

The average temperature of coffee in the sample, which is 70.2.

Step-by-step explanation:

The population is all the costumers. The company has determined that they want the average coffee temperature to be 65 degrees C. So, 65 degrees C is the average of the population.

The sample is the 20 orders. The mean $\mu$ of the sample is 70.2C(That is, the mean of the 20 orders0. So, the correct answer is:

The average temperature of coffee in the sample, which is 70.2.

3 0

3 years ago