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S_A_V [24]
3 years ago
13

A company is evaluating a new biology program that is supposed to improve test scores. The box plots show the the results of bio

logy test given before and after using the program. With the data, what is the most reasonable answer to the question: does the program improve test scores?
Mathematics
2 answers:
rjkz [21]3 years ago
5 0

Answer:

No, because the median test score decreased 5 points.

Step-by-step explanation:

The middle line is is the median so, if the pre-test is 60 and the post-test is 55 then there is a 5 point difference.

SOVA2 [1]3 years ago
3 0

Answer:

No, because the median test score decreased 5 points.

Step-by-step explanation:

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Answer:

  1. 3.61unit .I hope the answer is correct. I hope I will get 5 points
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3 years ago
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7. If SK = 13x - 5, KY= 2x + 9, and SY = 36-x, find each value.
sweet [91]

Answer:

SY=34, SK=21 and KY=13

Step-by-step explanation:

we have that

SY=SK+KY

substitute the given values

(36-x)=(13x-5)+(2x+9)

solve for x

36-x=15x+4

15x+x=36-4

16x=32

x=2

<em>Find the value of SY</em>

SY=(36-x)=36-2=34

<em>Find the value of SK</em>

SK=(13x-5)=13(2)-5=21

<em>Find the value of KY</em>

KY=(2x+9)=2(2)+9=13

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3 years ago
What is the common multiple of 7,5, and 8
zavuch27 [327]
The LCM is 280.

Please thank the answer if it helped you out!
3 0
3 years ago
A researcher is interested in finding a 95% confidence interval for the mean number minutes students are concentrating on their
Sever21 [200]

Answer:

A. Normal

B. Between 40.08 minutes and 43.92 minutes.

C. About 95 percent of these confidence intervals will contain the true population mean number of minutes of concentration and about 5 percent will not contain the true population mean number of minutes of concentration.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

Question A:

By the Central Limit Theorem, a normal distribution.

Question B:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{12}{\sqrt{150}} = 1.92

The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.92 = 40.08 minutes

The upper end of the interval is the sample mean added to M. So it is 42 + 1.92 = 43.92 minutes

Between 40.08 minutes and 43.92 minutes.

Question C:

x% confidence interval -> x% will contain the true population mean, (100-x)% wont.

So, 95% confidence interval:

About 95 percent of these confidence intervals will contain the true population mean number of minutes of concentration and about 5 percent will not contain the true population mean number of minutes of concentration.

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3 years ago
Find the ratio a:b, if it is given that 5a−3b=7b
VladimirAG [237]

Answer:

ab : a/2

Step-by-step explanation:

5 0
4 years ago
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