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Sedaia [141]
3 years ago
11

Barium metal has a body-centered cubic lattice with all atoms at lattice points; its density is 3.51 g/cm3. From these data and

the atomic weight, calculate the edge length of a unit cell.
Biology
1 answer:
stiks02 [169]3 years ago
7 0

Answer:

The unit cell's edge length is 5.06\times 10^{-8} m

Explanation:

Number of atom in BCC unit cell = Z = 2

Density of barium metal= 3.51g/cm^3

Edge length of cubic unit cell= a  = ?

Atomic mass of Ba(M) = 137.33 g/mol

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

= density

Z = number of atom in unit cell

M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

3.51 g/cm3=\frac{2\times 137.33g/mol}{6.022\times 10^{23} mol^{-1}\times (a)^{3}}

a = 5.06\times 10^{-8} m

The unit cell's edge length is 5.06\times 10^{-8} m

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