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rjkz [21]
3 years ago
13

What is the Ph of a 3.9* 10^-8 M OH- solution

Chemistry
1 answer:
Maksim231197 [3]3 years ago
3 0
Molarity = 3.9 * 10 ^ -8

pH = - log (3.9 * 10 ^ -8)

pH = - (-7.40893539)

pH = 7.409 = 7.4 ... Ans
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What mass of Ca(NO3)2 must be dissolved in 726.0 g of water to prepare a 0.200 m solution? Use molar masses with at least as man
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Answer:

The answer to your question is 22.4 g of Ca(NO₃)₂

Explanation:

Data

mass of Ca(NO₃)₂ = ?

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Process

In Chemistry, there are two main units of concentration Molarity (M) and Molality (m). In this problem concentration is "m" then I will calculate molality.

1) Formula

   molality = moles / mass of solvent

2.- Solve for moles

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-Substitution

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-Simplification

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3.- Convert moles to grams

Molar mass of Ca(NO₃)₂ = 40 + (14 x 2) + (6 x 16)

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                                       = 154 g

              154 g of Ca(NO₃)₂ ---------------- 1 mol

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                                    x = (0.1452 x 154) / 1

                                    x = 22.4 g of Ca(NO₃)₂

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When energy is transferred from the air to the water, what happens to most of the energy?
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