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3 years ago

What is the Ph of a 3.9* 10^-8 M OH- solution

Chemistry

1 answer:

Maksim231197 [3]3 years ago

3 0

Molarity = 3.9 * 10 ^ -8

pH = - log (3.9 * 10 ^ -8)

pH = - (-7.40893539)

pH = 7.409 = 7.4 ... Ans

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In reverse osmosis, water flows out of a salt solution until the osmotic pressure of the solution equals the applied pressure. I

Vsevolod [243]

Answer : The final concentration of the seawater is, 2.909 mole/L

Explanation :

Formula used for osmotic pressure :

$\pi=CRT$

where,

$\pi$ = osmotic pressure = 70.0 bar = 70 atm

R = solution constant = 0.0821 Latm/moleK

T= temperature of solution = $20^oC=273+20=293K$

C = final concentration of seawater = ?

Now put all the given values in the above formula, we get the concentration of seawater.

$70atm=C\times 0.0821Latm/moleK\times 293K$

$C=2.909mole/L$

Therefore, the final concentration of the seawater is, 2.909 mole/L

4 0

4 years ago

You titration 5.0 mL of HCl with 0.010 M NaOH. You find the end point of your titration occurs when 12.0 mL of NaOH has been add

Nookie1986 [14]

your answer is 0.00833M the volume was converted into liters

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Using the molarity equation, we can find the number of moles of HCl that reacted:

molarity=mol soluteL soln

mol solute=(molarity)(L soln)

mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl

(volume converted to liters)

Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:

0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH

Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:

molarity=mol soluteL soln

5 0

3 years ago

If you want to produce 11 moles of NH3, how much H2 do you need?

leva [86]

Answer:

33 g of H2

Explanation:

N2 + 3 H2 -> 2 NH3

3 mol H2 -> 2 mol NH3

x -> 11 mol NH3

x= (11 mol NH3 * 3 mol H2)/ 2 mol NH3

x= 16.5 mol H2

1 mol H2 -> 2 g

16.5 mol H2 ->x

x= (16.5 mol H2 * 2 g)/ 1 mol H2

x= 33 g

3 0

3 years ago

Please help me understand this.

masya89 [10]

I cant see what your asking

7 0

3 years ago

Read 2 more answers

The oxidizing agent our bodies use to obtain energy from food is oxygen (from the air). If you breathe 17 times a minute (at res

nata0808 [166]

Answer:

The volume of the air breath per day is =12240 L day ^ -1 and he volume of oxygen breathe each day is= 2570.4 L

Explanation:

Complete question: The oxidizing agent our bodies use to obtain energy from food is oxygen (from the air). If you breathe 17 times a minute (at rest), taking in and exhaling 0.50 L of air with each breath, what volume of air do you breathe each day? Air is 21% oxygen by volume. what volume of oxygen do you breathe each day?

Solution

Given that,

The volume of the air with each breath = 0.50L

The frequency of breath is = 17 times per minute

the next step is to calculate the volume of the air breath per day

The volume of the breathed air = volume of air breathed/ breath * 17 breaths/min * 60 minutes / per hour * 24 hours/ per day

= 0.50L/ breath * 17 breath /min * 60 minutes / per hour * 24 hours/ per day

= 12240 L day ^ -1

The next step is to calculate the oxygen breathed per day:

The volume of oxygen breathed = volume of air breathed * percent oxygen in air/100

= 12240 L day ^ -1 * 21 /100

= 2570.4 L day ^ -1

Therefore for each day, the volume of oxygen breathe is 2570.4 L

5 0

4 years ago

Read 2 more answers