Answer:
The answer is attached below
Explanation:
To draw the Lewis structure the sulphur willl be placed in the centre with the Valence electron sorrounding it the electrons between sulphu and oxygen to form bonds
The empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.
<h3>How to calculate empirical formula?</h3>
The empirical formula of a compound is a notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.
The empirical formula of the given compound can be calculated as follows:
- Hafnium = 55.7% = 55.7g
- Chlorine = 44.3% = 44.3g
First, we convert mass values to moles by dividing by the molar mass of each element
- Hafnium = 55.7g ÷ 178.49g/mol = 0.312mol
- Chlorine = 44.3g ÷ 35.5g/mol = 1.25mol
Next, we divide each mole value by the smallest
- Hafnium = 0.312 ÷ 0.312 = 1
- Chlorine = 1.25 ÷ 0.312 = 4
Therefore, the empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.
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Answer:
Different compounds react with oxygen differently – some contain lots of heat energy while others produce a smaller amount. The reaction with the oxygen may happen very quickly or more slowly. Amount: The amount of fuel available to burn is known as the fuel load.
Explanation:
Answer:
The volume of a given mas of a gas is directly proportional to the temperature if the pressure remains constant
V is directly proportional to T
V=1/T
V=constant/T
Explanation: