Answer:
40.88 kPa.
Explanation:
Given that,
Volume, V₁= 4.2 L
Pressure, P₁ = 110 kPa
We need to find the pressure of the gas when the volume is changed to 11.3L at constant temperature.
According to Boyle's law, at constant temperature, volume is inversely proportional to the pressure. Mathematically,
So, the new pressure is 40.88 kPa.
Answer: the concentration of [CO]= 0.0532M
Explanation:
From The equation of reaction
2H2(g) + CO(g) ⇌ CH3OH(g)
Applying Kc= [CH3OH]/[H2]^2[[CO]
[CH3OH]= 0.00487
[CO]= x-0.00487
[H2]=(0.032-0.00487)^2=0.0271
Substitute into formula
Kc=[CH3OH]/[H2]^2[[CO]
35= 0.00487/(0.0271)^2(x-0.00487)
Simplify
x-0.00487=0.189
x= 0.00487+0.189=0.193moles
[CO]= n/C= 0.193/3.63= 0.0532M
Hi there!
There is a total of 22 atoms in this compound. (Add all the numbers)
Could you Brainliest me, please?
