Left to right. Whatever comes first (multiplication or division) you do. This is all part of the PEMDAS/Order of operations.
Hopefully I solved your problem! :)
Answer:
N= -4
Step-by-step explanation:
Since mid-point of -13 and 3 is -4.
Answer:
Step-by-step explanation:
Let x represent the number of years it will take the two colleges to have the same enrollment.
In 2000, there were 12900 students at college A, with a projected enrollment increase of 900 students per year. This means that the expected number of students at college A in x years time is
12900 + 900x
In the same year, there were 25,000 students at college B, with a projected enrollment decline of 700 students per year. This means that the expected number of students at college B in x years time is
25000 - 700x
For both colleges to have the same enrollment,
12900 + 900x = 25000 - 700x
900x + 700x = 25000 - 12900
1600x = 12100
x = 12100/1600
x = 7.56
Approximately 8 years
The year would be 2000 + 8 = 2008
<span>I think any of those estimates are correct since we don't have a value for the width and length so acquiring the actual measurement its impossible. All possible answers are correctly written in square units.</span>
Answer: ((x^2 + 3)^9)/9 +c
Step-by-step explanation:
Let, x² + 3 = u
⇒2x dx = du
Now, substituting, we get,
∫u^8 du
= (u^(8+1))/(8+1)
= (u^9)/9
= ((x^2 + 3)^9)/9 +c
