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Debora [2.8K]
4 years ago
6

Animal behavior researchers often refer to an activity associated with punishment or reward as a(n) 

Mathematics
2 answers:
lesya [120]4 years ago
5 0

Answer:

There are the options

A) operant

B) condition

C) stimulus

D) response

The answer is A. Operant

Step-by-step explanation:

Operant is a type of associative learning. It is the process in which the strength of a behavior is altered by reinforcement or punishment.

In operant conditioning, the stimuli present when the behavior is rewarded or punished is what controls the behavior.

Verizon [17]4 years ago
3 0
Operant conditioning, right?

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31 in the form 2n -1
____ [38]

Answer:

(2 × 16) - 1

Step-by-step explanation:

31 = 2n - 1

31 + 1 = 2n

32 = 2n

16 = n

therfore, 31 can be written as :-

<h3>31 = (2 × 16) - 1</h3>
3 0
3 years ago
Is 4:5 (4/5) less, or greater than 19:30 (19/30)?
liberstina [14]
4/5 is greater because when you times it by 6 the numerator becomes 24 therefore it is greater
6 0
4 years ago
Read 2 more answers
An elementary school is in a growing suburb. The school’s principal estimates that the current enrollment of 750 students will i
HACTEHA [7]

Answer:

62.9% in ten years

Step-by-step explanation:

This type of growth corresponds to what is called an exponential growth, since in the expression for the number of students keep including the multiplication of the same factor as the years go by, Let's start by analyzing what happens the first year:

The initial enrollment of 750 is expected to grow by 5%, therefore after one year the enrollment should be:

After one year = Year_1 = 750 + 5% increase = 750+750*0.05=750(1+0.05)

where we have used the decimal form of 5% as he factor 0.05 multiplying 750 (the initial enrollment) to give the increase.

After the second year, we consider a starting value of Year_1 enrollments that will increase another 5%, which gives: Year_2 = Year_1 + Year_1 * 0.05= Year_1 (1 + 0.05).

So replacing Year_1 by its original expression (750(1+0.05)) we notice that Year_2 = 750 * (1+0.05) * (1+0.05) = 750 * (1+0.05)^2

We can go on with this same reasoning and find that each year includes a new factor (1+0.05) to the new increasing enrollment.

At the end of 10 years, the number of enrollment will be:

750*(1+0.05)^10=1221.67

which we can round to 1222 students enrolled

This means and increase of: \frac{1222-750}{750} =0.62933

That is approximately 62.9%

6 0
3 years ago
A count went up from 450 to 600. What was the approximate percent increase
liq [111]

Answer:

33.33%

Step-by-step explanation:

well answer choices would help so I know which percentage they want but a 150 increase from 450 to 600 is about 1/3 or 33.33% of 450 and is about 1/4 or 25% of 600 but based on the structure of the question im willing to wager they want 33.33% increase on 450 is 600

5 0
3 years ago
Richard had 180 total minutes to do
zaharov [31]
3(x+4)= 3x+12
3x+12+x+3+x=5x + 15
5x+15=180
5x=180-15
5x=165
x=165/5
x= 33min

mowing the grass = 3(x+4)
= 3(33+4)
=99+12
=111 min mowing grass
3 0
3 years ago
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