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marishachu [46]

3 years ago

8

(08.05)

1 answer:

Readme [11.4K]3 years ago

5 0

The mistake is in step 3:

I: −2m =−12 − 2n
II: 2m = 8 + 8n

the student set both right sides of the equations equal (−12 − 2n = 8 + 8n), but the left sides aren't equal: first equation has -2m, second has +2m so the signs of one of the equations must be inverted first

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Explain the difference between the graphs of :

charle [14.2K]

Answer:

The only difference is that for any positive value of 'x' g(X) and h(X) will be same and for any negative value of 'x' g(x) and h(x) will be different.

Step-by-step explanation:

Given

$f(x)= |x|$

$g(x) = |x+5|\\\\h(x)= |x| +5$

|x| is modulus of x so modulus makes negative value as psoitive

for example

$|3|= 3$

$|-3|=3$

now we will solve for the above

For $x=4$

$g(4)=|4+5|\\=|9|\\=9$

and

$h(4)=|4| +5\\=4 +5\\=9$

Now for $x=-4$

$g(-4)=|-4+5|\\=|1|\\=1$

and

$h(-4)=|-4| +5\\=4 +5\\=9$

so for positive value it is same and for negative value it is different

7 0

3 years ago

A population, P, of birds is doubling in size each year, according to the model P = 100(2t), where t reperesents years. What was

mina [271]

The initial population size was 200

5 0

2 years ago

Read 2 more answers

Use the definition f ′(x) = h0f(x + h) - f(x)h to find the derivative. f(x)=x+2

NNADVOKAT [17]

Answer:

f'(x) = 1

General Formulas and Concepts:

<u>Calculus</u>

Limit Properties: $\lim_{n \to a} c = c$
Definition of a Derivative: $f'(x)= \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x + 2

<u>Step 2: Find derivative</u>

Substitute: $f'(x)= \lim_{h \to 0} \frac{((x + h) + 2)-(x+2)}{h}$
Distribute: $f'(x)= \lim_{h \to 0} \frac{x + h + 2-x-2}{h}$
Combine like terms: $f'(x)= \lim_{h \to 0} \frac{h}{h}$
Divide: $f'(x)= \lim_{h \to 0} 1$
Evaluate: $f'(x)= 1$

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2 years ago

Which expression is equivalent to the expression 22 – 10 – 7.5?

Sergeu [11.5K]

Answer:

24.5-9-6

Step-by-step explanation:

3 0

3 years ago

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Please Solve for x<br> Log15 1 =x

Fiesta28 [93]

$\bold{\log_{15} (1) = x}\\\\
\bold{\Longrightarrow~~~15^x = 1}\\\\
\Longrightarrow~~~\boxed{\bold{x = 0}}$

3 0

2 years ago