Answer:
the answer is letter B. the entropy
• The bond that exist between the CCl4 compound ,forms a covalent bond ,, this can be illustrated in the diagram below:
• We can see that it contains four non-polar covalent bond between carbon and chloride
Answer:
Check the explanation
Explanation:
Kindly check the attached images below to see the step by step explanation to the question above.
Answer:
Monosaccharides are the simplest form of carbohydrates that cannot be hydrolyzed to smaller compounds. Monosaccharides are the basic units of carbohydrates and are also known as simple sugars.
The monosaccharides are classified on the basis of number of carbon atoms present.
Triose is a type of monosaccharide molecule, which is composed of 3 carbon atoms.
Tetrose is a type of monosaccharide molecule, which is composed of 4 carbon atoms.
Pentose is a type of monosaccharide molecule, which is composed of 5 carbon atoms.
Hexose is a type of monosaccharide molecule, which is composed of 6 carbon atoms.
D-glucose is a hexose sugar and it is the <u>most abundant monosaccharide</u> in the nature.
Answer:
0.083
Explanation:
Explanation:
We're asked to find the molar concentration (molarity) of the HCl solution, given some titration measurements.
Let's first write the chemical equation for this neutralization reaction:
NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)
Since we're given the molarity and volume of the NaOH solution used, we can calculate the moles be using the molarity equation:
mol solute=(molarity)(L soln)
=(0.1molL)(0.0332L)=0.00332 mol NaOH
Since all the coefficients in the chemical equation are 1, the relative number of moles of HCl used is also 0.00332 mol.
Finally, let's use the molarity equation again to find the molarity of the HCl solution (given the volume of NaOH soln is 40 mL, which must be in liters when using molarity equations):
molarity=mol soluteL soln
=0.00332lmol HCl0.040lL=0.083M