Question

For the Ag ground-state ion, predict the type of orbital from which an electron will need to be removed to form the ion of greater positive charge.

Answer 1

Answer:

For the Ag ground-state ion, the type of orbital from which an electron will need to be removed to form the ion of greater positive charge is :

s-orbital

Explanation:

Naming of orbitals :

s = s-orbital

p = p-orbital

d = d-orbital

The electronic configuration of Ag is :

$[Kr]4d^{10}5s^{1}$

The Outermost shell = 5s

so electron should be removed from 5s . there is only 1 electron in 5s -shell. Hence , Ag exist +1 oxidation state.

According to Aufbau's Rule : Electron will be filled first in lower energy orbital.

The electron should be removed first ,from the higher energy orbital.This is because high energy orbitals are away from the nucleus and can be easily removed. The outermost electron feel less attraction of the nucleus

Ionization energy : Energy required to remove the electron from the outermost shell of the element in the gaseous state.

$Ag\rightarrow Ag^{+} +e^{-}$

Hence it will form Ag+ cation

Ag+:

$[Kr]4d^{10}$

Outer shell is removed after loss of electron.