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Bas_tet [7]
3 years ago
14

A thermometer is in a beaker of water. Which statement best explains why the thermometer reading initially increases when LiBr(s

) is dissolved in the water?
(1) The entropy of the LiBr(aq) is greater than the entropy of the water.
(2) The entropy of the LiBr(aq) is less than the entropy of the water.
(3) The dissolving of the LiBr(s) in water is an endothermic process.
(4) The dissolving of the LiBr(s) in water is an exothermic process.
Chemistry
1 answer:
fiasKO [112]3 years ago
8 0
<span>(4) The dissolving of the LiBr(s) in water is an exothermic process</span>
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Ethene is the first member of the
DanielleElmas [232]
It will be:

b. Alkyne* series

* You have done a spelling mistake here. It will be "Alkene" not  "Alkyne".
5 0
3 years ago
Copper has two naturally occurring isotopes. Cu−63 has a mass of 62.939 amu and relative abundance of 69.17%.
fiasKO [112]
The answer is 64.907 amu.

The atomic mass of an element is the average of the atomic masses of its isotopes. The relative abundance of isotopes must be taken into consideration, therefore:
atomic mass of copper = atomic mass of isotope 1 * abundance 1 + atomic mass of isotope 2 * abundance 2

We know:
atomic mass of copper = 63.546 amu
The atomic mass of isotope 1 is: 62.939 amu
The abundance of isotope 1 is: 69.17% = 0.6917
The atomic mass of isotope 1 is: x
The abundance of isotope 2: 100% - 69.17% = 30.83% = 0.3083

Thus:
63.546 amu = 62.939 amu * 0.6917 + x * 0.3083
63.546 <span>amu = 43.535 amu + 0.3083x
</span>⇒ 63.546 amu - 43.535 amu = 0.3083x
⇒ 20.011 amu = 0.3083x
   ⇒ x = 20.011 amu ÷ 0.3083 = 64.907 amu
7 0
3 years ago
Help in chem please!!!!!!
IgorLugansk [536]

This is a one-step unit analysis problem.  Since we are staying in moles, grams of our compound, and thus molar mass, is not needed.

1 mole is equal to 6.022x10²³ particles as given, so:

1.5x10^{24} particles FeO_{2} (\frac{1mol}{6.022x10^{23}particles } )=2.49 molFeO_{2}

<h3>Answer:</h3>

2.49 mol

Let me know if you have any questions.

3 0
3 years ago
A glucose solution has a density of 1.02 g/ml. what is its specific gravity
Makovka662 [10]
Answer is: specific gravity of glucose is 1,02.
d(glucose) = 1,02 g/ml.
d(water) = 1,00 g/ml.
Specific gravity of glucose = density of glucose ÷ density of water.
Specific gravity of glucose = 1,02 g/ml ÷ 1,00 g/ml.
Specific gravity of glucose = 1,02.
Specific gravity<span> is the ratio of the </span>density<span> of a substance (in this case glucose) to the density of a reference substance (water).</span>
4 0
3 years ago
Read 2 more answers
Which two changes would increase the gravitational force between two
scoundrel [369]

Answer:

B. Increase the mass of one of the objects.

E. Decrease the distance between the objects.

Explanation:

To effect an increase in the gravitational force between two objects, the mass of both objects should be increased and the distance between them reduced.

This is derived from the Newton's law of universal gravitation:

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Therefore, if the mass of the two bodies are increased and the distance between them reduced, the gravitational force of attraction will increase.

4 0
3 years ago
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