3 years ago

SOMEONE PLEASE HELPPP

Chemistry

1 answer:

xxTIMURxx [149]3 years ago

5 0

A is the correct awnser Beacuse it ether right kne

You might be interested in

Select the answer that CANNOT be used to fill in the blank in the following sentence:

8_murik_8 [283]

Answer:

the answer is ur mom

Explanation:

8 0

3 years ago

What is Ka for HCN(aq) H+(aq)+CN-(aq)?

Ierofanga [76]

HCN is a weak acid, with A Ka = 4.0 x 10-10.

7 0

3 years ago

A concentration cell is constructed using two Ni electrodes with Ni2+ concentrations of 1.0 M and 1.00 � 10�4 M in the two half-

Komok [63]

Answer: The cell potential of the cell is +0.118 V

Explanation:

The half reactions for the cell is:

Oxidation half reaction (anode): $Ni(s)\rightarrow Ni^{2+}+2e^-$

Reduction half reaction (cathode): $Ni^{2+}+2e^-\rightarrow Ni(s)$

In this case, the cathode and anode both are same. So, $E^o_{cell}$ will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Ni^{2+}_{diluted}]}{[Ni^{2+}_{concentrated}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = ?

$[Ni^{2+}_{diluted}]$ = $1.00\times 10^{-4}M$

$[Ni^{2+}_{concentrated}]$ = 1.0 M

Putting values in above equation, we get:

$E_{cell}=0-\frac{0.0592}{2}\log \frac{1.00\times 10^{-4}M}{1.0M}$

$E_{cell}=0.118V$

Hence, the cell potential of the cell is +0.118 V

5 0

3 years ago

The heating curve below shows the temperature change that occurs as a solid is heated. What is occurring at segment BC of the gr

Anettt [7]

If Bc is the first horizontal line there, the solid is melting and going into the liquid state

6 0

3 years ago

DNA replication results in two identical DNA molecules. What role do DNA helicases have in DNA replication?

PilotLPTM [1.2K]

I'm pretty sure since one chemical can only bind with one other type, um, I think that one side of the DNA helicase helps make the other side?

8 0

4 years ago

Read 2 more answers

SOMEONE PLEASE HELPPP​

SOMEONE PLEASE HELPPP