Base = Height, Let them be x.

Solve quadratic equation:
x=6, x=-2(rejected because base and height is positive)
6x6/2 =18
Diagonals that bisect each other are perpendicular and form a right angle.
AEB is a right triangle.
We can apply the Pythagorean theorem:
c^2 = a^2+b^2
Where c is the hypotenuse (longest side) and a and b the other 2 legs.
Replacing:
AB^2 = AE^2+BE^2
AB^2 = 5^2+12^2
AB^2 = 25+144
AB^2 = 169
AB=√169 = 13
Lenght of AB= 13
The cross section of the satellite dish is an illustration of a quadratic function
The quadratic function that models the cross-section is y = 1/6(x^2 - 9)
<h3>How to determie the equation of the cross-section?</h3>
The given parameters are:
Width = 6 feet
Depth = 1.5 feet
Express the width the sum of two equal numbers
Width = 3 + 3
The above means that, the equation of the cross section passes through the x-axis at:
x = -3 and 3
So, we have:
y = a(x - 3) * (x + 3)
Express as the difference of two squares
y = a(x^2 - 9)
The depth is 1.5.
This is represented as: (x,y) =(0,-1.5)
So, we have:
-1.5 = a(0^2 - 9)
Evaluate the exponent
-1.5 = -9a
Divide both sides by -9
a = 1/6
Substitute 1/6 for a in y = a(x^2 - 9)
y = 1/6(x^2 - 9)
Hence, the quadratic function that models the cross-section is y = 1/6(x^2 - 9)
Read more about quadratic functions at:
brainly.com/question/1497716
If you are asking what is the graph of y = 3x^2 -2x+1.
Then, the attached file would be the answer.
To check, b^2 - 4(a)(c), for each equation and use these facts:
If b^2 - 4(a)(c) = 0, there is only one real root meaning, the graph touches the x-axis only in one point.
If b^2 - 4ac > 0, there are two real roots meaning, the graph touches the x-axis in two different points.
If b2 - 4ac < 0, there are no real roots then the graph does not touch the x-axis. This would be the case for y = 3x^2 - 2x + 1.
Solution:
(-2)^2 -4(3)(1) = 4 - 12 = -8 < 0 will result in not real roots.
18x can also be expressed as:
= 2x * (4+5)
= 2x * 9
= 18x
ANSWER: 2x * (4 + 5)
Hope this helps! :)