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fomenos
3 years ago
13

Given two linear equations, explain how you can determine if the lines are parallel without graphing them

Mathematics
1 answer:
alexira [117]3 years ago
7 0
Hello : 
let A and B two points in the first line calculate the slope : <span>:   (YB - YA)/(XB -XA)
</span>let C and D two points in the second line calculate the slop  (YC - YD)/(XC -XD)
you are slope 
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The length of the base and the height of a triangle are numerically equal. Their sum is 6 less than the number of units in the a
Troyanec [42]
Base = Height, Let them be x.

( x \times x) \div 2 = (x + x) + 6 \\ x ^{2} \div 2 = 2x + 6 \\ \frac{1}{2} x^{2} - 2x - 6 = 0
Solve quadratic equation:
x=6, x=-2(rejected because base and height is positive)

6x6/2 =18
6 0
3 years ago
In rhombus ABCD, the diagonals AC and BDintersect at E. If AE=5 and BE=12, what is thelength of AB?
hram777 [196]

Diagonals that bisect each other are perpendicular and form a right angle.

AEB is a right triangle.

We can apply the Pythagorean theorem:

c^2 = a^2+b^2

Where c is the hypotenuse (longest side) and a and b the other 2 legs.

Replacing:

AB^2 = AE^2+BE^2

AB^2 = 5^2+12^2

AB^2 = 25+144

AB^2 = 169

AB=√169 = 13

Lenght of AB= 13

8 0
10 months ago
Satellite dishes are shaped like parabolas to optimally revive signals. The cross section of a satellite dish can be modeled by
Anna11 [10]

The cross section of the satellite dish is an illustration of a quadratic function

The quadratic function that models the cross-section is y = 1/6(x^2 - 9)

<h3>How to determie the equation of the cross-section?</h3>

The given parameters are:

Width = 6 feet

Depth = 1.5 feet

Express the width the sum of two equal numbers

Width = 3 + 3

The above means that, the equation of the cross section passes through the x-axis at:

x = -3 and 3

So, we have:

y = a(x - 3) * (x + 3)

Express as the difference of two squares

y = a(x^2 - 9)

The depth is 1.5.

This is represented as: (x,y) =(0,-1.5)

So, we have:

-1.5 = a(0^2 - 9)

Evaluate the exponent

-1.5 = -9a

Divide both sides by -9

a = 1/6

Substitute 1/6 for a in y = a(x^2 - 9)

y = 1/6(x^2 - 9)

Hence, the quadratic function that models the cross-section is y = 1/6(x^2 - 9)

Read more about quadratic functions at:

brainly.com/question/1497716

7 0
2 years ago
Which equation could generate the curve in the graph below?y=3x^2-2x+1
4vir4ik [10]
If you are asking what is the graph of y = 3x^2 -2x+1.

Then, the attached file would be the answer.

To check, b^2 - 4(a)(c), for each equation and use these facts:

If b^2 - 4(a)(c) = 0, there is only one real root meaning, the graph touches the x-axis only in one point.

If b^2 - 4ac > 0, there are two real roots meaning, the graph touches the x-axis in two different points.

If b2 - 4ac < 0, there are no real roots then the graph does not touch the x-axis. This would be the case for y = 3x^2 - 2x + 1.
Solution:
(-2)^2 -4(3)(1) = 4 - 12 = -8 < 0 will result in not real roots. 

7 0
3 years ago
Help with this question please!!
notsponge [240]
18x can also be expressed as:

= 2x * (4+5)
= 2x * 9
= 18x

ANSWER: 2x * (4 + 5)

Hope this helps! :)
3 0
3 years ago
Read 2 more answers
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