Answer:
see below
Step-by-step explanation:
I enter the equation into a graphing calculator and let it do the graphing.
___
If you're graphing this by hand, you start by looking for the parent function. Here, it is |x|. That has a vertex of (0, 0) and a slope of +1 to the right of the vertex and a slope of -1 to the left of the vertex.
Here, the function is multiplied by -3/2, so will open downward and have slopes of magnitude 3/2 (not 1). The graph has been translated 5 units upward, so the vertex is (0, 5).
I'd start by plotting the vertex point at (0, 5), then identifying points with slope ±3/2 either side of it. To the left, it is left 2 and down 3 to (-2, 2). The points on the right of the vertex are symmetrically located about the y-axis, so one of them will be (2, 2).
Of course, you don't plot any function values for x > 4.
Answer: 36.9
Step-by-step explanation:
For this question you have to find out whether you are using Sin, Cos or Tan.
To work out which one you are using you can use SOH CAH TOA to help you.
SOH- The 'S' is for Sin, the 'O' and the 'H' is for Opposite over Hypotenuse.
CAH- The 'C' is for Cos and the 'A' and the 'H' is for Adjacent over Hypotenuse.
TOA- The 'T' is for Tan, the 'O' and the 'A is for Opposite over Adjacent.
As you have the Opposite (the side opposite the angle we're looking for) and the Adjacent (the side next to the angle were looking for) we would be using Tan.
So first you would have to write:
Tanθ=3/4
Then because we want Theta (θ) on it's own we would have to do the inverse to 'undo' the equation. Tan-1 is the inverse of Tan.
θ=Tan-1 3/4
To find the answer you would have to put it in your calculator.
θ=36.9
Hope this helps :)
7(10 visits) ≤ 68
70 ≤ 68
Not Viable
7(9 visits) ≤ 68
63 ≤ 68
Viable
The first solution is not viable because 10 visits will give a total cost of $70 per month, which is $2 over his monthly budget of $68.
The second solution is viable. He could visit the gym a maximum of 9 times per month for a total of $63 a month and that will be under his $68 monthly budget.
Hope this helps! :)
The answer is B) 20 lbs for $22 because carol is getting 8 pounds more for only $9+
Answer:
a) Average velocity at 0.1 s is 696 ft/s.
b) Average velocity at 0.01 s is 7536 ft/s.
c) Average velocity at 0.001 s is 75936 ft/s.
Step-by-step explanation:
Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
.
To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s.
, b. 0.01 s.
, c. 0.001 s.
Solution :
a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.
![(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.1%5C%20s%7D%3D%5Cfrac%7B%5Ctext%7BChange%20in%20height%7D%7D%7B0.1%7D)
![(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.1%5C%20s%7D%3D%5Cfrac%7Bh_%7B2.1%7D-h_2%7D%7B0.1%7D)
![(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.1%5C%20s%7D%3D%5Cfrac%7B%2870%282.1%29-16%282.1%29%5E2%29-%2870%280.1%29-16%280.1%29%5E2%29%7D%7B0.1%7D)
![(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.1%5C%20s%7D%3D%5Cfrac%7B69.6%7D%7B0.1%7D)
![(\text{Average velocity})_{0.1\ s}=696\ ft/s](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.1%5C%20s%7D%3D696%5C%20ft%2Fs)
b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.
![(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.01%5C%20s%7D%3D%5Cfrac%7B%5Ctext%7BChange%20in%20height%7D%7D%7B0.01%7D)
![(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.01%5C%20s%7D%3D%5Cfrac%7Bh_%7B2.01%7D-h_2%7D%7B0.01%7D)
![(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.01%5C%20s%7D%3D%5Cfrac%7B%2870%282.01%29-16%282.01%29%5E2%29-%2870%280.01%29-16%280.01%29%5E2%29%7D%7B0.01%7D)
![(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.01%5C%20s%7D%3D%5Cfrac%7B75.36%7D%7B0.01%7D)
![(\text{Average velocity})_{0.01\ s}=7536\ ft/s](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.01%5C%20s%7D%3D7536%5C%20ft%2Fs)
c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.
![(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.001%5C%20s%7D%3D%5Cfrac%7Bh_%7B2.001%7D-h_2%7D%7B0.001%7D)
![(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.001%5C%20s%7D%3D%5Cfrac%7B%2870%282.001%29-16%282.001%29%5E2%29-%2870%280.001%29-16%280.001%29%5E2%29%7D%7B0.001%7D)
![(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.001%5C%20s%7D%3D%5Cfrac%7B75.936%7D%7B0.001%7D)
![(\text{Average velocity})_{0.001\ s}=75936\ ft/s](https://tex.z-dn.net/?f=%28%5Ctext%7BAverage%20velocity%7D%29_%7B0.001%5C%20s%7D%3D75936%5C%20ft%2Fs)