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3 years ago

Help please I'm trying to graduate (Only #3)

Mathematics

1 answer:

lesya [120]3 years ago

5 0

The pieces shown are like all of 8 slices of a pizza.

the area of cirlce = area of the rectangle formed by rearranging the pizza slices.
= (pi*r)*r

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Define the points P(negative 4−4,negative 2−2) and Q(33,negative 4−4). Carry out the following calculation. Find two vecto

slega [8]

Answer:

The required vectors are $u=$ and $v=$ .

Step-by-step explanation:

Given information: P(-4,-2) and Q(3,-4).

We need to find the two vectors parallel to $\overrightarrow {QP}$ with length 2.

If $A(x_1,y_1)$ and $B(x_2,y_2)$ , then

$\overrightarrow {AB}=$

$|\overrightarrow {AB}|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the above formula we get

vector QP is,

$\overrightarrow {QP}==$

Magnitude of vertor QP is,

$|\overrightarrow {QP}|=\sqrt{(-4-3)^2+(-2-(-4))^2}$

$|\overrightarrow {QP}|=\sqrt{(-7)^2+(2)^2}$

$|\overrightarrow {QP}|=\sqrt{49+4}$

$|\overrightarrow {QP}|=\sqrt{53}$

Using vector is

$\widehat {QP}=\frac{\overline {QP}}{|\overline {QP}|}$

$\widehat {QP}=\frac{1}{\sqrt{53}}$

$w=\widehat {QP}=\frac{1}{\sqrt{53}}$

Multiply vector w by 2 to get a parallel vector parallel of QP in same direction.

$u=2w=$

Multiply vector w by -2 to get a parallel vector parallel of QP in opposite direction.

$v=-2w=$

Therefore the required vectors are $u=$ and $v=$ .

8 0

3 years ago

On Saturday, Craig rode his bike 5/8 of a mile. On Sunday, he rode his bike 1/2 of a mile. Craig added 5/8 + 1/2 to find the tot

saul85 [17]

Hi there!

Craig's reason is not reasonable because when you add fractions you have to find equivalent fractions.

The total distance in miles would be 1 1/8 miles.

By using a number line, line up the fractions, so then you could add them both.

Hope this helps :)

8 0

3 years ago

Estoy realmente aburrido, así que aquí están algunos de mis puntos ~ ¿Cuál es la respuesta a la cosa en la captura de pantalla?

Virty [35]

Answer:

c = 7x

Step-by-step explanation:

espero que esto ayude

7 0

2 years ago

For every problem-solving activity it's crucial that no less than five alternatives be considered.

matrenka [14]

Yes this is true. For every problem-solving activity it's crucial that no less than five alternatives be considered.

4 0

3 years ago

Read 2 more answers

Which congruency theorem can be used to prove<br> that ABD =DCA?

Dimas [21]

Answer:

The answer is "SAS".

Step-by-step explanation:

In this question we assume two angle is given that are:

$\ Two \ triangles \angle ABD \ and \angleDCA \\\\\ In \ this \ on \ angle \ is \ common \ that \ is, \\\\ AD=AD \\\\AB= CD \\\\\angle A \ is \ equal \ = \angle A \ (\ which \ is \ given)\\\\$

That's why SAS rule is correct.

6 0

3 years ago