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creativ13 [48]
3 years ago
5

Help please I'm trying to graduate (Only #3)

Mathematics
1 answer:
lesya [120]3 years ago
5 0
The pieces shown are like all of 8 slices of a pizza.

the area of cirlce = area of the rectangle formed by rearranging the pizza slices.
 = (pi*r)*r
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Work out the total number of mobile phones sold in the 3 years​
svetlana [45]

Answer: your wuestion isn’t specific enough.

Step-by-step explanation:

6 0
3 years ago
$800 at 3.8% interest for 6 months What is the interest? What is the new balance?
ycow [4]

Answer:

  • 800(1+0.038)2

Step-by-step explanation:

800(1+0.038)2

4 0
3 years ago
Read 2 more answers
Please answer ASAP. A baseball is hit upward from a platform that is m high at an initial speed of 29m/s. The approximate height
kotegsom [21]

Answer:

a) about 0.7 seconds to 5.1 seconds.

b) Listed below.

Step-by-step explanation:

h - 1 = -5x^2 + 29x

h = -5x^2 + 29x + 1

a) We will find the amount of time it takes to get to 18 meters.

18 = -5x^2 + 29x + 1

-5x^2 + 29x + 1 = 18

-5x^2 + 29x - 17 = 0

We will then use the quadratic formula to find the answer.

[please ignore the A-hat; that is a bug]

\frac{-29±\sqrt{29^2 - 4 * -5 * -17} }{2 * -5}

= \frac{-29±\sqrt{841 - 340} }{-10}

= \frac{-29±\sqrt{501} }{-10}

= \frac{-29 ± 22.38302929}{-10}

= \frac{-6.616970714}{-10} and \frac{-51.38302929}{-10}

= 0.6616970714 and 5.138302929

So, the time period for which the baseball is higher than 18 metres ranges from about 0.7 seconds to 5.1 seconds.

b) Restrictions on the domain and range of the function are that the domain and range can never be negative, since time cannot be negative, and height cannot be negative. The height cannot exceed the vertex of the parabola, since that is the highest the ball will ever go. It cannot exceed that height since gravity will cause the ball to fall down.

Hope this helps!

5 0
3 years ago
Click the photo )) give three numbers between -7 and 9 that satisfy the given condition.
Veronika [31]
13 3/39 is too big, it's greater than 9, so that one is out.
16 is an integer, so that one is out too.  99/6 = 16.5, which is greater than 9, so it can't be right

So the answer is the other 3
6 0
3 years ago
The average student loan debt for college graduates is $25,150.
Aleks04 [339]

Using the normal distribution, it is found that:

a) X \approx N(25150, 12050)

b) There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

c) Low: $23,519.65, High: $26,580.35.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 25150, \sigma = 12050.

Hence the distribution of X can be described as follows:

X \approx N(25150, 12050)

The probability that the college graduate has between $14,200 and $33,950 in student loan debt is the <u>p-value of Z when X = 33950 subtracted by the p-value of Z when X = 14200</u>, hence:

X = 33950:

Z = \frac{X - \mu}{\sigma}

Z = \frac{33950 - 25150}{12050}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

X = 14200:

Z = \frac{X - \mu}{\sigma}

Z = \frac{14200 - 25150}{12050}

Z = -0.91

Z = -0.91 has a p-value of 0.1814.

0.7673 - 0.1814 = 0.5859.

There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

Considering the symmetry of the normal distribution, the middle 10% is between the 45th percentile(X when Z = -0.127) and the 55th percentile(X when Z = 0.127), hence:

Z = \frac{X - \mu}{\sigma}

-0.127 = \frac{X - 25150}{12050}

X - 25150 = -0.127(12050)

X = $23,519.65.

Z = \frac{X - \mu}{\sigma}

0.127 = \frac{X - 25150}{12050}

X - 25150 = 0.127(12050)

X = $26,580.35.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

5 0
2 years ago
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