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mariarad [96]
3 years ago
11

Solve x2 – 8x + 15 < 0. Select the critical points for the inequality shown.

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
5 0

Answer:

x> 17/8

Step-by-step explanation:

add the numbers

17-8x<0

move the constant to the right-hand side and change its sign

-8x<-17

Divide both side of the inequality by -8 and flip the inequality sign

x>17/8

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3 years ago
What is the x of 2/3x squared minus 6x plus 15
iogann1982 [59]
(2/3)x^2 -6x + 15 = 0
Using the quadratic formula:
x = [-b +-sq root(b^2 - 4 *a*c)] / 2a
x= [--6 +-sq root(36 -4*(2/3)*15] / 2*(2/3)
x= [6 +-sq root 36 -40] / (4/3)

x1 = 4.5 + (2i / (4/3))
x1 = 4.5 + 1.5i
x2 = 4.5 - (2i / (4/3))
x2 = 4.5 - 1.5i




4 0
4 years ago
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