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4 years ago

A shoreline is eroding at a rate of 1/3 3 foot per 3 months. How many feet are eroding per year?

2 answers:

6 0

I am pretty sure you mean 1313 per 3 months, I just answered this question for someone else. The answer is 5252 feet a year<em>
</em>

salantis [7]4 years ago

4 0

7ft if 3+1/3 hopefully this helps i did hwat i can

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Please help I will give brainliest

Vika [28.1K]

Answer:

Brainliest?

8 0

2 years ago

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In a ten pin bowling the highest possible score in a single game is 300. At one point in the season, John had an average score o

Sindrei [870]

Answer:

John need to get 293 in his next game to bring his average up to 183.

Step-by-step explanation:

John starts with N games played and averaging 177 points per game.

In game N+1, John scored 199 points.

$\frac{177N + 199}{N+1}=178\\177N+199=178N+178\\N=21\\$

So, John has now played (N+1) = 22 games.

We need to know what score John needs in game 23 to bring his average to 183.

$\frac{177*21 + 199+Y}{23}=183\\3916+Y=4209\\Y=293\\$

8 0

2 years ago

Betty had $70. She bought a necklace for $9 and a ring for $7. Which expression correctly shows the total money Betty has left?

Elodia [21]

70 - 9 - 7 = x 70 being the original amount

4 0

3 years ago

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Carrie and brent leave home at the same time. carrie drives due east at a rate of 30 mph, while brent drives due south at a rate

Helga [31]

<h3>They are 268 miles far apart after 4 hours</h3>

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<u>Given :</u>

v₁ = 30 mph due east

v₂ = 60 mph due south

t = 4 hours

<u>Unknown :</u>

displacement = d = ?

<u>Solution :</u>

$d_1 = v_1 \times t$

$d_1 = 30 ~ mph \times 4 ~ h$

$d_1 = \boxed {120 ~ miles}$

$d_2 = v_2 \times t$

$d_2 = 60 ~ mph \times 4 ~ h$

$d_2 = \boxed {240 ~ miles}$

$d^2 = (d_1)^2 + (d_2)^2$

$d^2 = 120^2 + 240^2$

$d^2 = 72000$

$d = \sqrt{72000}$

$d = 120\sqrt{5} ~ miles$

$d \approx \boxed {268 ~ miles}$

<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

6 0

3 years ago

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Find the midpoint of the line segment with end coordinates of:(−1,7) and (3,−2)

SOVA2 [1]

Answer:

Step-by-step explanation:

mid point formula = (x1+x2/2 , y1+y2/2)

hence putt the values we get,

mid point = ( -1+3/2 , 7-2/2)

= (1 , 2.5)

5 0

3 years ago