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3 years ago

In the above lightwave the property labeled a determines which characteristic of visible light

Physics

1 answer:

kap26 [50]3 years ago

7 0

The light must be either very dim or else non-existent.
We can't see the light wave or the label.

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What materials are used on solar panels to allow them to produce electricity?

Softa [21]

Rays of sunlight hit the solar panel and are
absorbed by semi-conducting materials such as silicon.
Photovoltaic cells are
usually made from silicon, an excess material that constitutes more
than 28 percent of the Earth's crust.
These cells are created by bonding two
wafers of silicon that are connected to metal wires
The top water is silicon is thin and bottom is thicker the wafers produce electricity as absorb solar radiation
hope it helps

6 0

3 years ago

Near the poles, more energy is reflected back into space than is absorbed. near the poles, more energy is reflected back into sp

VladimirAG [237]

Correct answer: a) True.

In fact, the soil at the poles consists mainly of snow. Snow has an albedo of 90%: albedo is the fraction of light (and so, of energy) that is reflected back to the space. This means that at the poles, about 90% of the light is reflected back to the space, while only 10% is absorbed.

7 0

3 years ago

A helium tank holds a volume of .02 m^3 at a pressure of 15.5*10^6 Pa and a temperature of 293 K. How many spherical balloons wi

lukranit [14]

Answer:

Explanation:

We shall find the volume of stored gas at atmospheric pressure .

P₁ V₁ = P₂ V₂

15.5 x 10⁶ x .02 = 10⁵ x V₂ ( atmospheric pressure is 10⁵ Pa )

V₂ = 3.1 m³

volume of one balloon = 4/3 x π r³ , r is radius of balloon

= 4/3 π x .11³

= .050658 m³

no of balloon = total volume to be filled / volume of one balloon

= 3.1 / .050658

= 61 .2

= 61

7 0

3 years ago

A ball is dropped from rest at point O (height unknown). After falling for some time, it passes by a window of height 3 m and it

Usimov [2.4K]

Answer:

Part a)

$\Delta v_{down} = 4.8 m/s$

Part b)

$v_a = 3.71 m/s$

Explanation:

Since ball is dropped under uniform gravity

so here we can say that the distance of 3 m moved by the ball under uniform acceleration is given as

$d = (\frac{v_f + v_i}{2})t$

so we have

$3 = (\frac{v_f + v_i}{2})(0.49)$

$v_f + v_i = 12.24$

also we know that

$v_f - v_i = at$

$v_f - v_i = (9.81)(0.49)$

$v_f - v_i = 4.81$

now we will have

$v_f = 8.52 m/s$

$v_i = 3.71 m/s$

Part a)

$\Delta v_{down} = v_b - v_a$

$\Delta v_{down} = 8.52 - 3.71$

$\Delta v_{down} = 4.8 m/s$

Part b)

speed at the top of the window is

$v_a = 3.71 m/s$

3 0

3 years ago

A. Calculate the electric potential energy stored in a capacitor that stores <img src="https://tex.z-dn.net/?f=3.40%20x%2010%5E%

sertanlavr [38]

Part a)

As we know that energy stored inside the capacitor is given as

$U = \frac{1}{2}CV^2$

for a given capacitor we know

$Q = CV$

Now we can use it in above equation to find the energy

$U = \frac{1}{2}QV$

$U = \frac{1}{2}(3.4\times 10^{-6})(24)$

$U = 40.8\times 10^{-6} J$

PART b)

If two negative charges are hold near to each other and then released

Then due to mutual repulsion they start moving away from each other

Due to mutual repulsion as the two charges moving away the electrostatic potential energy of two charges will convert into kinetic energy of the two charges.

So here as they move apart kinetic energy will increase while potential energy will decrease

Part c)

As we know that capacitance is given as

$C = \frac{Q}{V}$