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Marina86 [1]
3 years ago
10

When the pressure at the bottom of a submerged object is greater than the pressure at the top of submerged object, buoyant force

is produced.
A. True
B. False
Physics
2 answers:
Ivanshal [37]3 years ago
8 0

Answer:

true!

Explanation:

ELEN [110]3 years ago
4 0
The answer would most like be true!
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NEED HELP ASAPTsunamis are often called tidal waves because they are caused by tides.
garik1379 [7]

Answer:

false

Explanation:

a tsunami is almost always caused by an earthquake under water.

5 0
2 years ago
23) A high school website directs parents to not allow student access to blue laser pointers or allow the students to bring them
vekshin1
Mainly because of the higher energy of blue light than red light.

In fact, light is made of photons, each one carrying an energy equal to
E=hf
where h is the Planck constant while f is the frequency of the light.
The frequency of red light is approximately 450 THz, while the frequency of blue light is about 650 Hz. Higher frequency means higher energy, so blue light is more energetic than red light and therefore it can cause more damages than red light.
6 0
3 years ago
What is the frame of reference for a plane moving at 500 km/h?
RUDIKE [14]
The frame of reference is the rotating earth underneath the flight path of the plane, the rate of rotation of the earth is 1036 miles per hour, meaning that the pilot has to compensate this fact when landing the aircraft.
3 0
3 years ago
Read 2 more answers
Hi
valkas [14]
I try to aim a the right key or do typing lessons
5 0
3 years ago
Read 2 more answers
4. A 1200 kg car traveling North at 20.0 m/s collides with a 1400 kg car traveling South at 22.0 m/s. The two
Dvinal [7]

Answer:-2.61 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum p_{o} must be equal to the final momentum p_{f}:

p_{o}=p_{f} (1)

Where:

p_{o}=mV_{o}+MU_{o} (2)

p_{f}=(m+M)V_{f} (3)

m=1200 kg is the mass of the first car

V_{o}=20 m/s is the velocity of the first car, to the North

M=1400 kg is the mass of the second car

U_{o}=-22 m/s is the mass of the second car, to the South

V_{f} is the final velocity of both cars after the collision

mV_{o}+MU_{o}=(m+M)V_{f} (4)

Isolating V_{f}:

V_{f}=\frac{mV_{o}+MU_{o}}{m+M} (5)

V_{f}=\frac{(1200 kg)(20 m/s)+(1400 kg)(-22 m/s)}{1200 kg+1400 kg} (6)

Finally:

V_{f}=-2.61 m/s (7) This is the resulting velocity of the wreckage, to the south

7 0
3 years ago
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