Which of the following statements is true for scientific theories and laws?

1 answer:

7 0

Essentially laws and theories are the same thing. In modern day science we don't generate "laws" per se, we call highly tested and sound hypotheses "theories" rather than laws. As such, both things can (and should) be questioned if there is repeatable evidence to support a contradiction. This is what keeps science moving forward.
For example we have Newton's Laws of motion which were shown to be only approximations by the theory of relativity. These were long held as true Laws of Nature but are actually incorrect.

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Monochromatic light with wavelength 588 nm is incident on a slit with width 0.0351 mm. The distance from the slit to a screen is

Norma-Jean [14]

Answer:

Explanation:

A. Using

Sinစ= y/ L = 0.013/2.7= 0.00481

စ=0.28°

B.here we use

Alpha= πsinစa/lambda

= π x (0.0351)sin(0.28)/588E-9m

= 9.1*10^-2rad

C.we use

I(စ)/Im= (sin alpha/alpha) ²

{= (sin0.091/0.091)²

= 3*10^-4

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A 75.5-kg person puts on a life jacket, jumps into the water, and floats. The jacket has a volume of 3.38 x 10-2 m3 and is compl

Andreyy89

Answer:

Density of jacket will be $680.4733kg/m^3$

Explanation:

We know that weight of water displaced= buoyant force=weight of man

Now volume of water displaced $v=3.38\times 10^{-2}+6.42\times 10^{-2}=9.8\times 10^{-2}m^3$

Density of water $d=100kg/m^3$

So weight of water displaced $=9.8\times 10^{-2}\times 1000=98kg$

So weight of jacket = 98-75 = 23 kg

We have given volume of the jacket = $3.38\times 10^{-2}m^3$

So density of jacket $=\frac{mass}{volume}=\frac{23}{3.38\times 10^{-2}}=680.4733kg/m^3$

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What is the sum of all forces acting on an object and direction

babunello [35]

The sum of all forces on an object is the net force or resultant force. If all the forces cancel out , resultant force is zero , otherwise unbalanced force will cause acceleration of object .

Force is the vector, has both direction and magnitude.

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Assuming that 70 percent of the Earth’s surface is covered with water at average depth of 0.95 mi, estimate the mass of the wate

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Answer:

The mass of the water on earth is $5.4537\times10^{20}\ kg$