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alina1380 [7]
3 years ago
9

What is the current through a wire if 240 coulombs of charge pass through the wire in 2.0 minutes?

Physics
2 answers:
xenn [34]3 years ago
4 0
Current = charge/time = 240/2x120 =1A.
Current flowing is 1 ampere. 
Oksana_A [137]3 years ago
3 0

Answer : Current flowing, I = 2 Ampere

Explanation :

It is given that,

Charge passing through a wire, q = 240 coulombs

Time taken to pass the charge, t = 2 minutes = 120 seconds

Electric current is defined as the ratio of the electric charge divided by time taken to pass the charge.

Mathematically, it can be written as :

I=\dfrac{q}{t}

Putting the value of q and t we get:

I=\dfrac{240\ C}{120\ s}

I = 2 Ampere

So, the current passing through the wire is 2 Amps.

Hence, this is the required solution.

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A solenoid is designed to produce a magnetic field of 3.50×10^−2 T at its center. It has a radius of 1.80 cm and a length of 46.
Anna11 [10]

Answer:

a. 2143 turns/m

b. 111.5 m

Explanation:

a. The minimum number of turns per unit length (N/L) can be found using the following equation:

B = \frac{\mu_{0}NI}{L}

\frac{N}{L} = \frac{B}{\mu_{0}I} = \frac{3.50 \cdot 10^{-2} T}{4\pi \cdot 10^{-7} Tm/A*13.0 A} = 2143 turns/m

Hence, the minimum number of turns per unit length is 2143 turns/m.

b. The total length of wire is the following:

N = 2143 turns/m*L = 2143 turns/m*46.0 \cdot 10^{-2} m = 986 turns

Since each turn has length 2πr of wire, the total length is:

L_{T} = N*2\pi r = 986 turn*2*\pi*1.80 \cdot 10^{-2} m = 111.5 m

Therefore, the total length of wire required is 111.5 m.

I hope it helps you!

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