To solve this, first subtract 6x from both sides.
That is because there cannot be the same variable on both sides of the equation. The new equation would be:
6x=24
Now divide by both sides of the equation by 6
x=4
Hope this helped! Tell me if you have any more questions!
Alright, 1, 2, and 4 are correct but 3 is not.
The error you made could be hard to notice but it was made. So let's put the equation up, 6x-(2x-9)=-31. Your error occurred when you didn;t distribute the negative sign for (2x-9), if you woud have distributed it then the equation would then be simplified into 6x-2x+9=31. You then add like terms and get 4x+9=31, subtract 9 on both sides and you'll get 4x=22. Divide 4 on both sides to isolate the variable and you get x=5.5
<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
Note that the equation of the circle is
(x-h)² +(y-k)² =r²
where centre is (h,k)
the equation of the circle based on the information given
(x-3)² +(y-4)² =r²
and the point on the circle (3,-2)
substitute into the equation
(3-3)² +(-2-4)² =r²
r=6 or r=-6
since r is radius, we reject r=-6 since radius must be nonnegative.
the radius is 6
