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3 years ago

The total amount of energy in an object is called __________ energy.

Chemistry

2 answers:

allochka39001 [22]3 years ago

4 0

The answer should be D) electrical

Oxana [17]3 years ago

3 0

Its internal energy, did you make a mistake with the options?

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Which statement describes the feeling interactions between frogs and insects? Select all that apply.

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2 years ago

One mole of nitrogen and one mole of neon are combined in a closed container at STP.How big is the container?V = __________ L

cestrela7 [59]

Answer : The volume of container will be 44.8 L

Explanation :

At STP condition,

The temperature and pressure are 273 K and 1 atm respectively.

As we know that at STP, 1 mole of substance occupies 22.4 L volume of gas.

As per question,

1 mole of nitrogen gas occupies 22.4 L volume

and,

1 mole of neon gas also occupies 22.4 L volume

Thus, total volume will be:

Total volume of container = 22.4 + 22.4 = 44.8 L

Hence, the volume of container will be 44.8 L

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3 years ago

Why can't all mixtures be classified as solutions?

shusha [124]

D. Not all mixtures are heterogeneous

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3 years ago

10 m3 of carbon dioxide is originally at a temperature of 50 °C and pressure of 10 kPa. Determine the new density and volume of

Dimas [21]

Answer : The new density and new volume of carbon dioxide gas is 0.2281 g/L and $7.2m^3$ respectively.

Explanation :

First we have to calculate the new or final volume of carbon dioxide gas.

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 10 kPa

$P_2$ = final pressure of gas = 15 kPa

$V_1$ = initial volume of gas = $10m^3$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $50^oC=273+50=323K$

$T_2$ = final temperature of gas = $75^oC=273+75=348K$

Now put all the given values in the above equation, we get:

$\frac{10kPa\times 10m^3}{323K}=\frac{15kPa\times V_2}{348K}$

$V_2=7.2m^3$

The new volume of carbon dioxide gas is $7.2m^3$

Now we have to calculate the new density of carbon dioxide gas.

$PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}$

Formula for new density will be:

$\rho_2=\frac{P_2M}{RT_2}$

where,

$P_2$ = new pressure of gas = 15 kPa

$T_2$ = new temperature of gas = $75^oC=273+75=348K$

M = molar mass of carbon dioxide gas = 44 g/mole

R = gas constant = 8.314 L.kPa/mol.K

$\rho$ = new density

Now put all the given values in the above equation, we get:

$\rho_2=\frac{(15kPa)\times (44g/mole)}{(8.314L.kPa/mol.K)\times (348K)}$

$\rho_2=0.2281g/L$

The new density of carbon dioxide gas is 0.2281 g/L

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2 years ago

How can you identify an element that is a metalloid?

Dominik [7]

On the periodic table, the elements colored yellow, which generally border the stair -step line , are considered to be metalloids

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3 years ago