Hi,

Solving:

$x^{3} + 3x^{2} - 4x - 12 = 0 \\ {x}^{2} \times (x + 3) - 4x - 12 = 0 \\ {x}^{2} \times (x + 3) - 4(x - 3) = 0 \\ (x + 3) \times ( {x}^{2} - 4) = 0 \\ x + 3 = 0 \\ {x}^{2} - 4 = 0 \\ \\ (results) \\ x1 = - 3 \\ x2 = - 2 \\ x3 = 2$

Hope this helps.
r3t40

4 0

3 years ago

Jet001 [13]

Answer:

It is A

Step-by-step explanation:

8 0

3 years ago

AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to AB ?

Aleksandr [31]

Answer:

3y + 5x = 0

Step-by-step explanation:

The slope of the line = (y2-y1) / (x2-x1) = (5-0)/(-6-(-3))

= 5 / -3 = -5/3

Using the point-slope form , the line that passes through the origin and parallel to this line is

y - 0 = -5/3(x - 0)

y = -5/3 x

Multiply through by 3:-

3y = -5x

5x + 3y = 0

3 0

3 years ago