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Dvinal [7]
3 years ago
10

a school has 415 third grade and 338 second graders how many more third graders are there than second graders?

Mathematics
2 answers:
Alika [10]3 years ago
6 0

Answer:

There are 77 more third graders than there are second graders.

Step-by-step explanation:

You just have to subtract 338 from 415 to get your answer.

Pavlova-9 [17]3 years ago
3 0
There are 77 more third graders you can find this by doing 415-338.
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Answer: They are not inverse.

Step-by-step explanation:

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Please help I am confused will give brainly. Not sure how to find the measurements of 2, 3 and 4
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Answer:

2: 99° 3: 81° 4: 81°

Step-by-step explanation:

2 is supplementary to 1 so subtract 81 from 180 = 99.

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Write the following inequality in slope-intercept form. −6x + 2y ≤ 42
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Add the 6x to both sides. Then divide both sides by 2 to get y by itself.

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The sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number.
Tema [17]

Answer:

2 \frac{1}{16}

Step-by-step explanation:

The question state that;  the sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number.

First, we need to interpret and represent this statement mathematically

Let n be the number.

The sum means 'addition'

1/6 of that number is  1/6 of n = 1/6 × n  = \frac{n}{6}

2 1/2 of that number is 2 1/2 of n = 2 1/2 × n  = 5/2 × n = \frac{5n}{2}

So the question says that, when we add; \frac{n}{6} ,  \frac{5n}{2}  and 7 all together, the value is 12 1/2

That is;

\frac{n}{6}  + \frac{5n}{2} + 7 = 12 1/2

\frac{n}{6}  + \frac{5n}{2} + 7  = \frac{25}{2}         ( changing 12 1/2 to improper fraction will give  \frac{25}{2} )

So we can now go ahead and solve for n

\frac{n}{6}  + \frac{5n}{2} + 7  = \frac{25}{2}  

subtract 7 from both-side of the equation

\frac{n}{6}  + \frac{5n}{2}   =  \frac{25}{2}   -   7

\frac{n + 15n}{6}  =   \frac{25 -14}{2}

\frac{16n}{6}      =    \frac{11}{2}

\frac{16n}{6}  can be reduced to give us \frac{8n}{3}

\frac{8n}{3}   =   \frac{11}{2}

Cross multiply

8n × 2  = 11× 3

16n = 33

Divide both-side of the equation by 16

\frac{16n}{16}    =   \frac{33}{16}

(On the left-hand side of the equation, 16 will cancel-out 16 leaving us with just, while  on the right-hand side of the equation 33 will be divided by 16)

n =  \frac{33}{16}     = 2\frac{1}{16}

Therefore the number is  2\frac{1}{16}

5 0
3 years ago
A figure has been dilated from the origin by a scale factor of
Darya [45]

Answer:

See Explanation

Step-by-step explanation:

The question has missing details. So, I'll solve using a general assumption.

Let one of the coordinates of the figure be

A = (x,y)

Let the scale factor be n

When dilated, the new figure is:

A' = n * A

A' = n * (x,y)

To return the image back to the original figure, the new scale factor mus be a reciprocal of the previous scale factor i.e. \frac{1}{n}

So:

A = A' * \frac{1}{n}

Substitute n(x,y) for A';

A = n(x,y) * \frac{1}{n}

A = \frac{n(x,y)}{n}

A = (x,y)

Take for instance:

A = (2,3)

n = 2 -- scale factor

A' = n * A

A' = 2 * (2,3)

A' = (4,6)

To get A from A', using the analysis above

A = \frac{1}{2} * (4,6)

A = (2,3)

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