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serg [7]
3 years ago
6

Find the shortest side of a triangle whose perimeter is 64

Mathematics
1 answer:
valentinak56 [21]3 years ago
3 0
Answer shortest side would
Be 18.
64 -18 = 46
46 divided by 2 = 23.
So if two of the sides was the same 18 would be the smallest one of the sides could be
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Answer:

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let a = (a1, a2) and b = (b1, b2) and c = (c1,c2) be three non zero vectors. if a1b2 - a2b1 is not equal to 0. then show three a
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Consider the contrapositive of the statement you want to prove.

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In this case, the contrapositive claims that

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or in matrix form,

\begin{pmatrix}c_1\\c_2\end{pmatrix} = \begin{pmatrix}a_1&b_1\\a_2&b_2\end{pmatrix}\begin{pmatrix}\alpha\\\beta\end{pmatrix}

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3 0
3 years ago
Use this graph of g to find g(1).<br><br> pls help !
kari74 [83]
I’m not really sure if it correct, g(1)=0 or g(1)=1??
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3 years ago
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