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serg [7]
3 years ago
6

Find the shortest side of a triangle whose perimeter is 64

Mathematics
1 answer:
valentinak56 [21]3 years ago
3 0
Answer shortest side would
Be 18.
64 -18 = 46
46 divided by 2 = 23.
So if two of the sides was the same 18 would be the smallest one of the sides could be
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What is 78/10 expressed as a decimal?
Pavel [41]

Answer:

7.8

Step-by-step explanation:

3 0
3 years ago
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Simplify.
Kazeer [188]
(1/2)^2 = 1/4
2-2/3 = 6/3 - 2/3 = 4/3

OK so:
(1/2)^2 - 6(2-2/3) = 1/4 - 6(4/3)
= 1/4 - 8
= 1/4 - 32/4
= -31/4
3 0
3 years ago
. 1<br> Find f<br> for the function f.<br> f(x) = 3x² + 3, x &gt; 0<br> And find the domain
konstantin123 [22]

Answer:

y = \sqrt{\frac{x-3}{3} }

Domain = [3, infinity)

Step-by-step explanation:

x = 3y^2 + 3

3y^2 = x - 3

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y = \sqrt{\frac{x-3}{3} }

8 0
3 years ago
How much longer is the hypotenuse of the triangle than its shorter leg?
RUDIKE [14]

This is an incomplete question, here is a complete question and image is also attached below.

How much longer is the hypotenuse of the triangle than its shorter leg?

a. 2 ft

b. 4 ft

c. 8 ft

d. 10 ft

Answer : The correct option is, (b) 4 ft

Step-by-step explanation:

Using Pythagoras theorem in ΔACB :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(AB)^2=(AC)^2+(BC)^2

Given:

Side AC = 6 ft

Side BC = 8 ft

Now put all the values in the above expression, we get the value of side AB.

(AB)^2=(6)^2+(8)^2

AB=\sqrt{(6)^2+(8)^2}

AB=10ft

Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.

Difference = Side AB - Side AC

Difference = 10 ft - 6 ft

Difference = 4 ft

Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.

5 0
3 years ago
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Chocolate chip and peanut butter cookies are randomly chosen from a cookie jar and placed onto a plate. The first plate had four
soldier1979 [14.2K]

Answer:

3 peanut cookies

Step-by-step explanation:

Given that :

Plate 1:

Number of chocolate chip = 4

Number of peanut butter cookies = 1

Probability of drawing chocolate chip cookies from plate 1 :

Probability =( number of required outcome / Total possible outcomes)

P(chocolate chip) = 4 / 5

Plate 2:

Number of chocolate chip = 2

Number of peanut butter cookies = p

P(chocolate chip) = 2 / (2 + p)

Probability of drawing chocolate chip from plate 1 and then plate 2 = 8/ 25

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8 / (10 + 5p) = 8/ 25

8(10 + 5p) = 8 * 25

80 + 40p = 200

40p = 200 - 80

40p = 120

p = 3

7 0
2 years ago
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