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emmasim [6.3K]
3 years ago
6

Help me on this question

Mathematics
1 answer:
Maksim231197 [3]3 years ago
8 0

Hello!

If Estella decides to triple the height of this parallelogram then that will also affect the 5 ft on the left side as well because it is lined with the height of this shape.

I hope it helped!

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I need help with his math maze please
Aneli [31]

With these transversals across parallel lines the angles are either congruent or supplementary (adding to 180) and its pretty easy to figure out which is which, obtuse verse acute in the figure.

Each yellow circle indicates x and the path to the next square.  So for example the Start has alternate interior angles, which are congruent, so x is 141 degrees.

8 0
3 years ago
The expression 21 - (2x + 3)2 + 4 (1 - 1) + z3 can be simplified into the form
mr Goodwill [35]

Answer:

A=z

B=-2

C=0

D=30

Step-by-step explanation:

First lets simply the equation

21 - (2x +3)2 + 4(1-1) + z^3

21 - (2x^2 + 9) + 4(0) + z ^3

21 - 2x^2 + 9 + z^3

- 2x^2 + z ^3 + 30

This means that:

A=z

B=-2

C=0

D=30

5 0
4 years ago
Simplify completely quantity 8 x minus 56 over quantity x squared minus 49 divided by quantity x minus 6 over quantity x squared
34kurt
Hello

So the question ask to simplify the said equation. In getting its answer base on that equation you must first factor out each of them then find out the common of them to cancel them out that could lead you to your answer. In my calculation, the answer is D. 8 open parentheses x plus 4 close parentheses over quantity x minus 6. I hope this would help you


Have a nice day
6 0
4 years ago
Marisol is painting on a canvas that has an area of 180 square inches. The length of the painting is 11/4 times the width. What
Alona [7]
Notice the picture below, see the length "l"?

well \bf Area=l\times w\qquad 
\begin{cases}
l=\frac{11}{4}w\\
Area=180
\end{cases}\\\\
-----------------------------\\\\
thus
\\\\
180=\cfrac{11}{4}w\times w

solve for "w", to find the width,

what's the length?  well, l = 11/4 w

3 0
3 years ago
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
3 years ago
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