Question

Does anyone know how to do this help please

Answer 1

Answer:

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

$\rm\implies y = x^2+x - 6$

Here we need to substitute the different values of x , to get the different values of y.

Put x = -3 :-

$\rm\implies y = 3^2-3-6$

$\rm\implies y = 9 - 3 - 6$

$\rm\implies y = 0$

Put x = -2 :-

$\rm\implies y = 2^2-2-6$

$\rm\implies y = 4 -2-6$

$\rm\implies y = -4$

Put x = -1 :-

$\rm\implies y = -1^2-1-6$

$\rm\implies y = 1 -1-6$

$\rm\implies y = -6$

Put x = 1 :-

$\rm\implies y = 1^2+1-6$

$\rm\implies y = 2 -6$

$\rm\implies y = -4$

Put x = 2 :-

$\rm\implies y = 2^2+2-6$

$\rm\implies y = 4 +2-6$

$\rm\implies y = 2$

Put x = 3 :-

$\rm\implies y = 3^2+3-6$

$\rm\implies y = 9 +3-6$

$\rm\implies y = 6$

Final table :-

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$