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Alik [6]
3 years ago
7

A restaraunt has 1,600 milligrams and there’s gotta be 10 people how many grams do you need

Mathematics
1 answer:
natita [175]3 years ago
8 0
You need 1.6 Grams. Hope this helped :P
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What is the answer of 4x if x=2
Semmy [17]

Answer:

8

Step-by-step explanation:

4(x)

4(2)

8

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3 years ago
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I need a lot of help
vova2212 [387]
15. 1/2 base * <span>hight ,</span> 1/2 * 11 * 6 = the answer is 33 cm^2

16. The "median" is the "middle" value in the list of numbers. To find the median, your numbers have to be listed in numerical order from smallest to largest, so you may have to rewrite your list before you can find the median. So the answer is 155.

17. <span>The mean is the usual average, so I'll add and then divide. (33+25+42+25+31+37+46+29+38) / 9 = 34

18. You have to draw a plot.</span>
4 0
3 years ago
A jeweler buys gold jewelry and resells the gold to a refinery. The jeweler buys gold for $1,235.55 per ounce, and then resells
Naddika [18.5K]

Answer:

The correct answer is $.

The question states that the jeweler bought and sold 73.5 ounces of gold, so all we need to do is multiply the price of buying and selling one ounce of gold by 73.5.

Buying - $1235.55 per ounce

Selling - $1376.44 per ounce

73.5 x 1235.55 = 90,812.93

73.5 ounces of gold cost $90,812.93.

73.5 x 1376.44 = 101,168.34

73.5 ounces of gold can be sold for $101,168.34.

Now, all we have to do is subtract the amount spent on the gold from the amount of money made in order to find the profit. This is because the amount of money the jeweler makes depends on how much more money they made by selling the gold than buying it.

$101,168.34 - $90,812.93 = $10,355.41

The jeweler made $10,355.41 by buying and reselling 73.5 ounces of gold.

5 0
4 years ago
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What is 21/99 in a decimal form
Norma-Jean [14]

Answer:

0.2121~

Step-by-step explanation:

It's a repeating number. 0.0212121212

7 0
4 years ago
What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .
VladimirAG [237]

Answer:

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1

Using the standard form of the equation:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

y = \pm \frac{a}{b} (x-h)+k

where;

\frac{a}{b} is the slope

From above;

(h,k) = 11, 100

a^2 = 100

a = \sqrt{100}

a = 10

b^2 =4

b = \sqrt{4}

b = 2

y = \pm \frac{10}{2} (x-11)+2

y = \pm 5 (x-11)+2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

\frac{a}{b} to be  the slope in the equation  y = \pm \frac{10}{2} (y-11)+2

\frac{a}{b}  = \frac{10}{2}

\frac{a}{b}  = 5

Thus, the  positive slope of the asymptote = 5

8 0
3 years ago
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