The effective temperature of a star is relative to the
fourth root of the luminosity and is contrariwise proportional to the square
root of the radius.
L = k R² T⁴
If the radius remains continuous, while the luminosity doubles, the temperature
must increase by a factor of the fourth root of two.
If L → 2L, then T → 1.189207115 T
So the answer is approximately 1.19 times.
It could be warmer solid, or liquid, or gas, depending on the pressure and the amount of heat added.
Based on the options above, I see how the last option would actually be most fitting to how "the part of the electromagnetic spectrum that is visible to the human eye". This would be in separate parts, which would be divided into a certain number, which would actually be only 7 ranges of wavelengths. And therefore, this last statement would actually go very well and it would actually be the correct answer. And this would all relate to how <span> the part of the electromagnetic spectrum that is visible to the human eye, it's based on it's own 7 division parts that it has.
Your answer: </span>
I believe the correct answer from the choices listed above is the first option. Decreasing a telescope's eyepiece focal length will increase magnification. <span>The magnification of the </span>telescope<span> image is (</span>focal length<span> of the objective) divided by (</span>focal length <span>of the </span>eyepiece<span>). Hope this answers the question.</span>