Reflection is the bouncing of light rays off of a surface. Which situation is NOT an example of reflection?
2 answers:
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Answer:
The work function of the metal is 2.226 eV.
Explanation:
Given;
wavelength of the violet light, λ = 427 nm = 427 x 10⁻⁹ m
maximum kinetic energy, K.E = 0.684 eV
The energy of the incident light is calculated as;
Apply Einstein's photoelectric equation;
E = Ф + K.E
where;
Ф is the work function of the metal
Ф = E - K.E
Ф = 2.91 eV - 0.684 eV
Ф = 2.226 eV.
Therefore, the work function of the metal is 2.226 eV.
Let's see what variables we've got first. Hmmm. We have:
Displacement, d = 28 m
Time taken, t = 11 s
Initial velocity, u = 0 m/s (at rest)
And now we need to find the final velocity, v. Among the 4 (or 5) equations of motions, there's no equation that will let us simply plug in the values and give an answer sigh. But fear not! We'll do it in steps.
I'm going to pick one of the motion equation to find more information:
I know everything except for a in this one, so I I'll use this! After plugging in values, I get a = 0.4628 m/s^2.
Now I'm going to use another motion equation that has v in it because that needs to be solved!
Now I know everything except dial velocity v. Nice!
v = 0 + (0.4628)(11)
Displacement, d = 28 m
Time taken, t = 11 s
Initial velocity, u = 0 m/s (at rest)
And now we need to find the final velocity, v. Among the 4 (or 5) equations of motions, there's no equation that will let us simply plug in the values and give an answer sigh. But fear not! We'll do it in steps.
I'm going to pick one of the motion equation to find more information:
I know everything except for a in this one, so I I'll use this! After plugging in values, I get a = 0.4628 m/s^2.
Now I'm going to use another motion equation that has v in it because that needs to be solved!
Now I know everything except dial velocity v. Nice!
v = 0 + (0.4628)(11)